Consider the following system at equilibrium where AHⓇPC15 (9) PC13 (g) + Cl₂ (9)O increasesdecreasesO remains the sameThe value of QcO is greater than KO is equal to KcO is less than KcThe reaction mustO run in the forward direction to reestablish equilibrium.O run in the reverse direction to reestablish equilibrium.O remain the same. It is already at equilibrium.=If the VOLUME on the equilibrium system is suddenly increased at constant temperature:The value of KeThe number of moles of Cl2 willO increasedecreaseO remain the same87.9 kJ, and Kc=0.0120, at 500 K:

Given eqm rxn:PCl5(g) <=> PCl3(g) + Cl2(g) Kc = 0.0120& ∆H° = 87.9 kJ For any reactionA)…

Answered: Consider the following system at…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following system at equilibrium where AHⓇ
PC15 (9) PC13 (g) + Cl₂ (9)
O increases
decreases
O remains the same
The value of Qc
O is greater than K
O is equal to Kc
O is less than Kc
The reaction must
O run in the forward direction to reestablish equilibrium.
O run in the reverse direction to reestablish equilibrium.
O remain the same. It is already at equilibrium.
=
If the VOLUME on the equilibrium system is suddenly increased at constant temperature:
The value of Ke
The number of moles of Cl2 will
O increase
decrease
O remain the same
87.9 kJ, and Kc
=
0.0120, at 500 K:

Expert Solution

Step 1: Concept of Reaction quotient & equilibrium constant

Given eqm rxn:

PCl₅(g) <=> PCl₃(g) + Cl₂(g)

Kc = 0.0120

& ∆H° = 87.9 kJ

For any reaction

A) When Q_C=K_C, then reaction mixture is at equilibrium.

B) When Q_C>K_C, then reaction mixture is not at equilibrium and in order to reestablish the equilibrium value of Q_C needs to be increased and reaction does so by moving in reverse direction.

C) When Q_C<K_C, then reaction mixture is not at equilibrium and in order to reestablish the equiibrium value of Q_C needs to be decreased and reaction does so by moving in forward direction.

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