Assume the reaction below is at equilibrium. N,(g) + 3H,(g) 5 2NH3 (g) + heat Which of the following would shift the equilibrium to the left? O A decrease of temperature O An increase in amount of N2 O A decrease in pressure O A decrease in amount of NH3
Assume the reaction below is at equilibrium. N,(g) + 3H,(g) 5 2NH3 (g) + heat Which of the following would shift the equilibrium to the left? O A decrease of temperature O An increase in amount of N2 O A decrease in pressure O A decrease in amount of NH3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Equilibrium and Le Chatelier's Principle**
Assume the reaction below is at equilibrium:
\[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) + \text{heat} \]
**Question**: Which of the following would shift the equilibrium to the left?
- A decrease of temperature
- An increase in the amount of \(\text{N}_2\)
- A decrease in pressure
- A decrease in the amount of \(\text{NH}_3\)
**Explanation**:
This question involves applying Le Chatelier's Principle, which predicts how a change in conditions can affect the position of the equilibrium in a chemical reaction. The reaction shown is the synthesis of ammonia, which is exothermic (releases heat).
- **A decrease of temperature** would shift the equilibrium towards the exothermic direction (right), producing more \(\text{NH}_3\).
- **An increase in the amount of \(\text{N}_2\)** would shift the equilibrium to the right, favoring the forward reaction.
- **A decrease in pressure** would shift the equilibrium towards the side with more moles of gas, which is the left side (reactants), because 1 mole of \(\text{N}_2\) and 3 moles of \(\text{H}_2\) on the left side make a total of 4 moles, compared to 2 moles of \(\text{NH}_3\) on the right side.
- **A decrease in the amount of \(\text{NH}_3\)** would also shift the equilibrium to the right, trying to replace the lost \(\text{NH}_3\).
**Correct Answer**: A decrease in pressure.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35844c14-8e0f-4ef2-9129-409849687b45%2F287fbf5e-e9f8-4cec-b875-f86e71947066%2F0k4pebh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemical Equilibrium and Le Chatelier's Principle**
Assume the reaction below is at equilibrium:
\[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) + \text{heat} \]
**Question**: Which of the following would shift the equilibrium to the left?
- A decrease of temperature
- An increase in the amount of \(\text{N}_2\)
- A decrease in pressure
- A decrease in the amount of \(\text{NH}_3\)
**Explanation**:
This question involves applying Le Chatelier's Principle, which predicts how a change in conditions can affect the position of the equilibrium in a chemical reaction. The reaction shown is the synthesis of ammonia, which is exothermic (releases heat).
- **A decrease of temperature** would shift the equilibrium towards the exothermic direction (right), producing more \(\text{NH}_3\).
- **An increase in the amount of \(\text{N}_2\)** would shift the equilibrium to the right, favoring the forward reaction.
- **A decrease in pressure** would shift the equilibrium towards the side with more moles of gas, which is the left side (reactants), because 1 mole of \(\text{N}_2\) and 3 moles of \(\text{H}_2\) on the left side make a total of 4 moles, compared to 2 moles of \(\text{NH}_3\) on the right side.
- **A decrease in the amount of \(\text{NH}_3\)** would also shift the equilibrium to the right, trying to replace the lost \(\text{NH}_3\).
**Correct Answer**: A decrease in pressure.
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