Assume the reaction below is at equilibrium. N,(g) + 3H,(g) 5 2NH3 (g) + heat Which of the following would shift the equilibrium to the left? O A decrease of temperature O An increase in amount of N2 O A decrease in pressure O A decrease in amount of NH3

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**Chemical Equilibrium and Le Chatelier's Principle**

Assume the reaction below is at equilibrium:

\[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) + \text{heat} \]

**Question**: Which of the following would shift the equilibrium to the left?

- A decrease of temperature
- An increase in the amount of \(\text{N}_2\)
- A decrease in pressure
- A decrease in the amount of \(\text{NH}_3\)

**Explanation**: 
This question involves applying Le Chatelier's Principle, which predicts how a change in conditions can affect the position of the equilibrium in a chemical reaction. The reaction shown is the synthesis of ammonia, which is exothermic (releases heat). 

- **A decrease of temperature** would shift the equilibrium towards the exothermic direction (right), producing more \(\text{NH}_3\).
- **An increase in the amount of \(\text{N}_2\)** would shift the equilibrium to the right, favoring the forward reaction.
- **A decrease in pressure** would shift the equilibrium towards the side with more moles of gas, which is the left side (reactants), because 1 mole of \(\text{N}_2\) and 3 moles of \(\text{H}_2\) on the left side make a total of 4 moles, compared to 2 moles of \(\text{NH}_3\) on the right side.
- **A decrease in the amount of \(\text{NH}_3\)** would also shift the equilibrium to the right, trying to replace the lost \(\text{NH}_3\).

**Correct Answer**: A decrease in pressure.
Transcribed Image Text:**Chemical Equilibrium and Le Chatelier's Principle** Assume the reaction below is at equilibrium: \[ \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) + \text{heat} \] **Question**: Which of the following would shift the equilibrium to the left? - A decrease of temperature - An increase in the amount of \(\text{N}_2\) - A decrease in pressure - A decrease in the amount of \(\text{NH}_3\) **Explanation**: This question involves applying Le Chatelier's Principle, which predicts how a change in conditions can affect the position of the equilibrium in a chemical reaction. The reaction shown is the synthesis of ammonia, which is exothermic (releases heat). - **A decrease of temperature** would shift the equilibrium towards the exothermic direction (right), producing more \(\text{NH}_3\). - **An increase in the amount of \(\text{N}_2\)** would shift the equilibrium to the right, favoring the forward reaction. - **A decrease in pressure** would shift the equilibrium towards the side with more moles of gas, which is the left side (reactants), because 1 mole of \(\text{N}_2\) and 3 moles of \(\text{H}_2\) on the left side make a total of 4 moles, compared to 2 moles of \(\text{NH}_3\) on the right side. - **A decrease in the amount of \(\text{NH}_3\)** would also shift the equilibrium to the right, trying to replace the lost \(\text{NH}_3\). **Correct Answer**: A decrease in pressure.
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