Consider the following Scenario: • Maximize z = 9x1 + 12x2 + 11x3 o Subject to 6x1 + 4x2 + X3 s 20 3x1 + 5x2 + 3x3 s 30 5x, + 3x2 + 5x3 S 21 X; 2 0
Consider the following Scenario: • Maximize z = 9x1 + 12x2 + 11x3 o Subject to 6x1 + 4x2 + X3 s 20 3x1 + 5x2 + 3x3 s 30 5x, + 3x2 + 5x3 S 21 X; 2 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![The values of the "2nd basic" variable in the first
iteration, is written as:
O (7.5, 0, 3, 1, 0, -0.5, 5)
O (-4.5, 0, 1.75, -1.25, 1,0, 5)
(45, 0, 3, 1, 0, -0.5,
5)
None of the answers.
O (5.4, 0, 3, 1, 0, -0.5, 5)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af4aba8-0edd-487b-bd65-0b50a189518c%2Fb19d660b-f1e6-445c-92c0-85153051d7a6%2F3ndjbs_processed.png&w=3840&q=75)
Transcribed Image Text:The values of the "2nd basic" variable in the first
iteration, is written as:
O (7.5, 0, 3, 1, 0, -0.5, 5)
O (-4.5, 0, 1.75, -1.25, 1,0, 5)
(45, 0, 3, 1, 0, -0.5,
5)
None of the answers.
O (5.4, 0, 3, 1, 0, -0.5, 5)
![Consider the following Scenario:
Maximize z = 9x1 + 12x2 + 11x3
o Subject to
6x, + 4x2 + X3 S 20
3x, + 5x2 + 3x3< 30
5x1 + 3x2 + 5x3 < 21
X; 20
The "new pivot row" of the first iteration is
written as:
None of the answers.
(1.5, 1, 0.25, 0.25, 0, 0, 5)
O (75, 1, 0.5, 0, 0, 0.25, 17.5)
O (7.5, 1, 0.5, 0, 0, 0.25, 17.5)
O (151 0.25 0.25 0 0 5)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af4aba8-0edd-487b-bd65-0b50a189518c%2Fb19d660b-f1e6-445c-92c0-85153051d7a6%2Frvo2h3p_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following Scenario:
Maximize z = 9x1 + 12x2 + 11x3
o Subject to
6x, + 4x2 + X3 S 20
3x, + 5x2 + 3x3< 30
5x1 + 3x2 + 5x3 < 21
X; 20
The "new pivot row" of the first iteration is
written as:
None of the answers.
(1.5, 1, 0.25, 0.25, 0, 0, 5)
O (75, 1, 0.5, 0, 0, 0.25, 17.5)
O (7.5, 1, 0.5, 0, 0, 0.25, 17.5)
O (151 0.25 0.25 0 0 5)
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