-pply Big-M method to solve the following L. P. P. : Maximize : z = x1 + 2x2 + 3x3 – X4 ubject to : X1 + 2x2 + 3x3 =15 2x1 + x2 + 5x3 = 20 X1 + 2x2 + x3 + X4 = 10 %3D X1, X2, X3, X4 2 0

Q: Solve the following LP using the simplex method. Maximize z = 4x1+3x2+6x3 subject to 3x1+x2+3x3 0

A: Given that Maximize z=4x1+3x2+6x3 subject to 3x1+x2+3x3≤302x1+2x2+3x3≤40             x1,x2,x3≥0

Q: max z = 3x₁ + Sx25x3 + 8x4 nx1 + x2 + x3 + 3x4 ≤ 7 -x₁- (s+n)x2 - X3 X4-2 X1, X2, X3, X4 20 -

A: (.) Given,           (.) standard form of maximization problem is,        then dual problem is given…

Q: D 3.2-5. Use the graphical method to demonstrate that the follow ing model has no feasible…

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Q: B. Convert primal problem to dual problem: Minimize Z = 4x₁ + 2x₂-x3 Subject to: x₁ + x₂ + 2x32 3…

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Q: Solve using artificial variables. Maximize z = 3x, + 2x2 subject to: X, + X, = 60 4x1 +2x, 2 140 5x,…

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Q: Solve the following problem by using the Simplex approach: Maximize Z = 4X1…

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Q: Solve the following minimization problem by using branch and bound method. Min x₁ - 2x₂ Subject to…

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Q: Use the simplex method (in tabular form) to solve the following problem Maximize: Z=5x,+9x2+X3…

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Q: minimize Z = 8x +212 subject to 2r, - 6x, s 12 5x, + 4x2 40 X1 + 2r, 12 X2 S 6 X1, X2 20

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Q: HW 4: Use the simplex method to solve the following problem and verify the solution by the graphical…

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Q: (i) Use x.and x.as the initial basic variables and apply simplex method to solve: Маximize: z - бх.…

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Q: ¹) solve the following PDE Using method. Y 22x + x 22y = xy the multiplier

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Q: asider the following problem: Maximize Z = 4.x1 + 5x2 3.x3 (1) (2) subject to -xị X2 + 2х3 0, æ3 <…

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Q: Must Solve using Langrange Multiplier a. Determine the solution to the following function: Maximize…

A: In method of lagrange's multipliers we find extrema of a function f(x,y) for a given condition…

Q: Use the simplex method to solve the linear Maximize z=X, + 2x2 + X3 + 10x4 subject to: X, + 5x, + Xg…

A: We solve given LPP by Simplex Method.

Q: Form the initial tableau, and identify the pivot element. Maximize g = 18x + 53y %3D subject to x-3y…

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Q: Consider the following 3D linear optimisation problem. maximize 2x2-x3+3 subject to r + a2+ a3 = 3…

A: The standard form of the given LPP is Maximize z=2x2-x3+3 subject to…

Q: Solve the following LP graphically: maximize 13x1 + 23x2 subjected to 5x1 + 15x2 0.

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Q: Over what range can the coefficient of x2 vary before the current solution is no longer optimal?…

A: To determine: The range over which the coefficient of x2 can vary before the current solution is no…

Q: Solve the optimization problem. Minimize F = 37x² + 37y2 with xy² = 16. F =

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Q: Use technology to maximize the following: Maximize f = 3x1+ 4x2 + 10x3 subject to xi + 3x2 + 2x3 0,…

A: Given linear programming problem is Maximize  f=3x1+4x2+10x3 subject to…

Q: Write the dual to the following problem. Maximize z = 2x1 + x2  + 3x3 + x4

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Q: Construct the dual problem. Minimize  z = – 5x1 – 15x2

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Q: Solve graphically the dual of the LLP Minimise: z=4w; +6w,+5w,-W4 Sub. to w, +w, 23 W; +w, –w,2-2…

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Q: Use the Lagrange multiplier method to optimize the objective function 3x? + y? – 2xy subject to the…

A: Given f(x) = 3x2 + y2 - 2xy Constraint: x + y = 6

Q: subject to

A: Given,           p=3x+2y+zsubject to           2x+y+z≤150      2x+2y+8z≤200          2x+3y+z≤320and…

Q: Solve by HEURISTIC METHOD. Maximize Z MAXIMIZAR Z=X1+ 5X2 +7X3+ 3X4 Sa. 7X1 + 3X2 + 2X3 +4X4 <21 8X1…

A: We have linear programming problem with us. Maximize Z=X1+5X2+7X3+3X4subject to, 7X1+3X2+2X3+4X4≤21…

Q: Maximize: Z = 4x1 + 5x2 subject to: 3x₁+ 6x₂ ≤ 36 4x1 + 2x2 ≤ 36 X1+ X₂ ≤ 8 Find the combinations of…

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Q: MAXIMIZARZ =X1+ 5X2 +7X3+ 3X4 Sa. 7X1 + 3X2 + 2X3 +4X4 <21 8X1 + 2X2 +3X3 +5X4<25 X1<4 X2 < 4 X3 < 1…

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Q: combination of the tw products given the fo equation will be: Maximize Z = 5x + 7y Subjec to: x + ys…

A: and x,y ≥0

Q: Use the simplex method to solve the following LP model Minimize Z = 8X₁ + 6X2 Subject to: 2X₁ + 4X2…

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Q: [3.6] Consider the following problem: Maximize - 3x1 subject to -₁ 2.11 X1 ++ 2x2 3x2 ≤ Σ 1 6 0 X₂…

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Q: min 2x + 3x3 + 4x +2x1r2- 2.x1r3-8x1 - 4x2 – 213 s.t. I1, 12, 13 20.

A: Follow the steps.