Consider the following sample data with mean and standard deviation of 20.5 and 5.4, respectively. (You may find it useful toreference the appropriate table: chi-square table or Ftable)ClassLess than 1010 up to 2020 up to 3030 or moreFrequency25956515a. Using the goodness-of-fit test for normality, specify the competing hypotheses in order to determine whether or not the data arenormally distributed.Ho: The data are normally distributed with a mean of 20.5 and a standard deviation of 5.4.; HA: The data are not normallydistributed with a mean of 20.5 and a standard deviation of 5.4.O Ho: The data are not normally distributed with a mean of 20.5 and a standard deviation of 5.4.; HA: The data are normallydistributed with a mean of 20.5 and a standard deviation of 5.4.Test statisticb. Calculate the value of the test statistic. (Round intermediate values to at least 4 decimal places and final answer to 3 decimalplaces.)

A sample data is given with mean of 20.5 and a standard deviation 5.4. A Chi-square goodness of fit…

Answered: Consider the following sample data with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You may need to use the appropriate appendix table or technology to answer this question. A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 72 and a standard deviation of 13. If 68 percent of the students received grades of C or better, what is the minimum score of those who received Cs? O 58.57 65.87 78.13 O 85.43
A supplier of digital memory cards claims that no more than 1% of the cards are defective. In a random sample of 600 memory cards, it is found that 3% are defective, but the supplier claims that this is only a sample fluctuation. How many populations? 01 What is the parameter? O tandard Deviation Variance Difference between Means Proportion Mean
If the population standard deviation is 9, then what is the variance? a. 9 b. 81 c. 3 d. 18
Below are the SPSS results of a related (dependent) samples t-test. Use the SPSS results to answer Questions 5, 6, and 7. Paired Samples Statistics Mean N Std. Deviation Std. Error Mean Pair 1 Statistics Posttest 57.1250 40 16.73962 2.64677 Statistics Pretest 49.9250 40 15.09014 2.38596 Paired Samples Test Paired Differences t df Sig. (2-tailed) Mean Std. Deviation Std. Error Mean Pair 1 Statistics Posttest - Statistics Pretest 7.200 12.313 ( a ) ( b ) ( c ) .001 Find the mean of the differences ( and standard deviation of the differences (Sd). Replace “a,” “b,” and “c” in the table above with the correct values. Round to the third decimal place. Do you think there is a statistically significant difference between the pretest and posttest at the .05 level of significance?
ANSWER THE FOLLOWING PROBLEMS SHOWING COMPLETE SOLUTION ENCLOSE FINAL ANSWER THANK YOU! topic: FUNDAMENTAL SAMPLING DISTRIBUTION
Consider the following sample data. Sample A: 5, 8, 11 Sample B: 64, 67, 70 Sample C: 1,015; 1,018; 1,021 (a) Find the mean and standard deviation for each sample. (b) What does this exercise show about the standard deviation? multiple choice The idea is to illustrate that the standard deviation is not a function of the value of the mean. The idea is to illustrate that the standard deviation is a function of the value of the mean.
Answer the chi-square questions using the data below. Use an ? of 0.10? B A 1 2 3 4 1 20 29 11 19 2 9 18 24 21 a) What is the appropriate test statistic? ---Select--- na z-test One-Sample t-test Independent-Samples t-test Related-Samples t-test One-Way ANOVA Within-Subjects ANOVA Two-Way ANOVA Correlation Slope Chi-Square GoF Chi-Square IndependenceCompute the statistic selected in a): b) Obtain/compute the appropriate values to make a decision about H0.Critical Value = ; Test Statistic = Decision: ---Select--- Reject H0 Fail to reject H0c) Compute the corresponding effect size(s) and indicate magnitude(s).If not appropriate, input and/or select "na" below.Effect Size = ; Magnitude: ---Select--- na trivial effect small effect medium effect large effect
The following is a sample of patient's calcium tests in mg/dL. 9.3 8.8 10.1 8.9 9.4 9.8 10.0 9.9 11.2 12.1 Find each of the following: The mean: The median: The third quartile: The standard deviation: The variance:
If the variance is 140.2, what is the Standard deviation from the following? a. 12.84 b. 15.56 c. 16.56 d. 11.84
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
answer e,f,g The following random sample was selected from a normal distribution: 4, 6, 3, 5, 9, 3. d. Assume that the sample mean x and sample standard deviation s remain exactly the same as those you just calculated but are based on a sample of n = 25 observations rather than n = 6 observations. Repeat parts a–c. What is the effect of increasing the sample size on the width of the confidence intervals? e. Use Rejection region to test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, ?<6. Use ? = .05. f. Use p-Value to test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, ? ≠6. Use ? = .05.
Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean. Identify the value of the test statistic. Source DF MS F Factor 3 13.500 4.500 5.17 0.011 Error 16 13.925 0.870 Total 19 27.425 Seleccione una: O A. 5.17 О В. 0.011 O C. 4.500 O D. 13.500

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