Consider the following reaction. Draw the product (s) and if more than one product is formed determine which one is the major one. Discuss your reasons! CI DMSO

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## Reaction Analysis and Product Determination

### Exercise

Consider the following reaction. Draw the product(s), and if more than one product is formed, determine which one is the major one. Discuss your reasons!

### Reaction Scheme

- **Reactants:**
  - Benzyl chloride with a chiral center
  - Diaza compound (likely diazabicyclooctane, commonly known as DABCO)
  - Solvent: Dimethyl sulfoxide (DMSO)

The reactants are shown in the chemical equation below:

![Reactants](image_placeholder)

\[ \text{Reactant: Benzyl chloride} + \text{DABCO} \underset{\text{solvent}}{\stackrel{\text{DMSO}}{\longrightarrow}} \text{Product(s)} \]

### Detailed Explanation

1. **Reactant Structures:**
   - The first reactant is a benzyl chloride derivative with a chiral center, indicated by the wedge notation.
   - The second reactant is a diaza compound with a bicyclic structure, commonly known as DABCO.

2. **Solvent:** 
   - DMSO is commonly used as an aprotic solvent to facilitate SN2 reactions.

### Mechanistic Insight

This reaction is likely proceeding through an SN2 mechanism:
- **Nucleophile:** DABCO acts as a strong nucleophile due to its nitrogen atoms.
- **Electrophile:** The benzylic carbon bonded to the chlorine in the benzyl chloride is prone to nucleophilic attack.

### Product(s)

**Major Product Formation:**
- The nucleophilic nitrogen from DABCO will attack the benzylic carbon, displacing the chloride ion.
- Given the SN2 mechanism, the attack will lead to inversion of configuration at the chiral center.

### Drawing the Major Product

The major product will have the following features:
- Benzyl group attached to a nitrogen from the diaza compound.
- Inverted configuration at the chiral center compared to the starting material.

### Discussion

- **Reason for Major Product:**
  - DABCO is a strong nucleophile, favoring an SN2 pathway.
  - DMSO, being an aprotic solvent, stabilizes the transition state and enhances nucleophilicity.
  
**Therefore, the product with inverted configuration at the chiral center is the major product.**
Transcribed Image Text:## Reaction Analysis and Product Determination ### Exercise Consider the following reaction. Draw the product(s), and if more than one product is formed, determine which one is the major one. Discuss your reasons! ### Reaction Scheme - **Reactants:** - Benzyl chloride with a chiral center - Diaza compound (likely diazabicyclooctane, commonly known as DABCO) - Solvent: Dimethyl sulfoxide (DMSO) The reactants are shown in the chemical equation below: ![Reactants](image_placeholder) \[ \text{Reactant: Benzyl chloride} + \text{DABCO} \underset{\text{solvent}}{\stackrel{\text{DMSO}}{\longrightarrow}} \text{Product(s)} \] ### Detailed Explanation 1. **Reactant Structures:** - The first reactant is a benzyl chloride derivative with a chiral center, indicated by the wedge notation. - The second reactant is a diaza compound with a bicyclic structure, commonly known as DABCO. 2. **Solvent:** - DMSO is commonly used as an aprotic solvent to facilitate SN2 reactions. ### Mechanistic Insight This reaction is likely proceeding through an SN2 mechanism: - **Nucleophile:** DABCO acts as a strong nucleophile due to its nitrogen atoms. - **Electrophile:** The benzylic carbon bonded to the chlorine in the benzyl chloride is prone to nucleophilic attack. ### Product(s) **Major Product Formation:** - The nucleophilic nitrogen from DABCO will attack the benzylic carbon, displacing the chloride ion. - Given the SN2 mechanism, the attack will lead to inversion of configuration at the chiral center. ### Drawing the Major Product The major product will have the following features: - Benzyl group attached to a nitrogen from the diaza compound. - Inverted configuration at the chiral center compared to the starting material. ### Discussion - **Reason for Major Product:** - DABCO is a strong nucleophile, favoring an SN2 pathway. - DMSO, being an aprotic solvent, stabilizes the transition state and enhances nucleophilicity. **Therefore, the product with inverted configuration at the chiral center is the major product.**
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