Consider the following reaction where Kc = 1.20×10-2 at 500 K: PCl5 (g) PCl3 (g) + Cl2 (g) A reaction mixture was found to contain 0.132 moles of PCl5 (g), 2.78×10-2 moles of PCl3 (g), and 4.44×10-2 moles of Cl2 (g), in a 1.00 liter container. Indicate True (T) or False (F) for each of the following: ___TF 1. In order to reach equilibrium PCl5(g) must be produced . ___TF 2. In order to reach equilibrium Kc must decrease . ___TF 3. In order to reach equilibrium PCl3 must be produced . ___TF 4. Qc is greater than Kc. ___TF 5. The reaction is at equilibrium. No further reaction will occur
Consider the following reaction where Kc = 1.20×10-2 at 500 K: PCl5 (g) PCl3 (g) + Cl2 (g) A reaction mixture was found to contain 0.132 moles of PCl5 (g), 2.78×10-2 moles of PCl3 (g), and 4.44×10-2 moles of Cl2 (g), in a 1.00 liter container. Indicate True (T) or False (F) for each of the following: ___TF 1. In order to reach equilibrium PCl5(g) must be produced . ___TF 2. In order to reach equilibrium Kc must decrease . ___TF 3. In order to reach equilibrium PCl3 must be produced . ___TF 4. Qc is greater than Kc. ___TF 5. The reaction is at equilibrium. No further reaction will occur
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the following reaction where Kc = 1.20×10-2 at 500 K:
PCl5 (g) PCl3 (g) + Cl2 (g)
A reaction mixture was found to contain 0.132 moles of PCl5 (g), 2.78×10-2 moles of PCl3 (g), and 4.44×10-2 moles of Cl2 (g), in a 1.00 liter container.
Indicate True (T) or False (F) for each of the following:
___TF 1. In order to reach equilibrium PCl5(g) must be produced .
___TF 2. In order to reach equilibrium Kc must decrease .
___TF 3. In order to reach equilibrium PCl3 must be produced .
___TF 4. Qc is greater than Kc.
___TF 5. The reaction is at equilibrium. No further reaction will occur.
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