Consider the following reaction where $ K_c = 5.10 \times 10^{-6} $ at 548 K.\[ \text{NH}_4\text{Cl}(s) \rightleftharpoons \text{NH}_3(g) + \text{HCl}(g) \]A reaction mixture was found to contain 0.0527 moles of $\text{NH}_4\text{Cl}(s)$, 0.00304 moles of $\text{NH}_3(g)$, and 0.00226 moles of $\text{HCl}(g)$, in a 1.00 liter container.Is the reaction at equilibrium?If not, what direction must it run in order to reach equilibrium?The reaction quotient, $ Q_c $, equals $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$.The reaction- $ \circ $ must run in the forward direction to reach equilibrium.- $ \circ $ must run in the reverse direction to reach equilibrium.- $ \circ $ is at equilibrium.

Temperature (T) = 548 KMoles of = 0.0527 molMoles of = 0.00304 molMoles of HCl = 0.00226 molVolume…

Answered: Consider the following reaction where…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following reaction where $ K_c = 5.10 \times 10^{-6} $ at 548 K.

\[ \text{NH}_4\text{Cl}(s) \rightleftharpoons \text{NH}_3(g) + \text{HCl}(g) \]

A reaction mixture was found to contain 0.0527 moles of $\text{NH}_4\text{Cl}(s)$, 0.00304 moles of $\text{NH}_3(g)$, and 0.00226 moles of $\text{HCl}(g)$, in a 1.00 liter container.

Is the reaction at equilibrium?

If not, what direction must it run in order to reach equilibrium?

The reaction quotient, $ Q_c $, equals $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$.

The reaction
- $ \circ $ must run in the forward direction to reach equilibrium.
- $ \circ $ must run in the reverse direction to reach equilibrium.
- $ \circ $ is at equilibrium.

Expert Solution

Step 1: Consider the given information as follows;

$NH subscript 4 Cl open parentheses straight s close parentheses space space rightwards harpoon over leftwards harpoon space NH subscript 3 open parentheses straight g close parentheses space space plus space space HCl open parentheses straight g close parentheses space space space space space space space space space space space semicolon space space space space space space space space space space space space space straight K subscript straight c equals 5.10 cross times 10 to the power of negative 6 end exponent$

Temperature (T) = 548 K

Moles of $NH subscript 4 Cl$ = 0.0527 mol

Moles of $NH subscript 3$ = 0.00304 mol

Moles of HCl = 0.00226 mol

Volume (V) = 1.00 L

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