Consider the following reaction: COCI,(g) CO(g) + Cl,(g) If 1.79×10 moles of COCI,(g), 0.470 moles of CO, and 0.287 moles of Cl, are at equilibrium in a 19.0L container at 832 K, the value of the equilibrium constant, Ke, is

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### Topic: Equilibrium Constant Calculation

**Reaction:**
\[ \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \]

**Given Data:**
- Moles of \(\text{COCl}_2\): \(1.79 \times 10^{-3}\) moles
- Moles of \(\text{CO}\): \(0.470\) moles
- Moles of \(\text{Cl}_2\): \(0.287\) moles
- Volume of container: \(19.0\) L
- Temperature: \(832\) K

**Task:**
Calculate the equilibrium constant \(K_c\) for the reaction under the given conditions. 

To do so, use the formula for the equilibrium constant:

\[
K_c = \frac{[\text{CO}][\text{Cl}_2]}{[\text{COCl}_2]}
\]

Where \([ \cdot ]\) represents the concentration in moles per liter. You will need to calculate the concentrations from the given moles and volume.
Transcribed Image Text:### Topic: Equilibrium Constant Calculation **Reaction:** \[ \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \] **Given Data:** - Moles of \(\text{COCl}_2\): \(1.79 \times 10^{-3}\) moles - Moles of \(\text{CO}\): \(0.470\) moles - Moles of \(\text{Cl}_2\): \(0.287\) moles - Volume of container: \(19.0\) L - Temperature: \(832\) K **Task:** Calculate the equilibrium constant \(K_c\) for the reaction under the given conditions. To do so, use the formula for the equilibrium constant: \[ K_c = \frac{[\text{CO}][\text{Cl}_2]}{[\text{COCl}_2]} \] Where \([ \cdot ]\) represents the concentration in moles per liter. You will need to calculate the concentrations from the given moles and volume.
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