Consider the following reaction: COCI,(g) CO(g) + Cl,(g) If 1.79×10 moles of COCI,(g), 0.470 moles of CO, and 0.287 moles of Cl, are at equilibrium in a 19.0L container at 832 K, the value of the equilibrium constant, Ke, is
Consider the following reaction: COCI,(g) CO(g) + Cl,(g) If 1.79×10 moles of COCI,(g), 0.470 moles of CO, and 0.287 moles of Cl, are at equilibrium in a 19.0L container at 832 K, the value of the equilibrium constant, Ke, is
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Topic: Equilibrium Constant Calculation
**Reaction:**
\[ \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \]
**Given Data:**
- Moles of \(\text{COCl}_2\): \(1.79 \times 10^{-3}\) moles
- Moles of \(\text{CO}\): \(0.470\) moles
- Moles of \(\text{Cl}_2\): \(0.287\) moles
- Volume of container: \(19.0\) L
- Temperature: \(832\) K
**Task:**
Calculate the equilibrium constant \(K_c\) for the reaction under the given conditions.
To do so, use the formula for the equilibrium constant:
\[
K_c = \frac{[\text{CO}][\text{Cl}_2]}{[\text{COCl}_2]}
\]
Where \([ \cdot ]\) represents the concentration in moles per liter. You will need to calculate the concentrations from the given moles and volume.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F49f4e77f-1c6d-4f3e-85bf-06d6d1c1a91f%2F00bffd4b-9d50-423f-80a3-2415c88b7143%2Fp953bk2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Topic: Equilibrium Constant Calculation
**Reaction:**
\[ \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \]
**Given Data:**
- Moles of \(\text{COCl}_2\): \(1.79 \times 10^{-3}\) moles
- Moles of \(\text{CO}\): \(0.470\) moles
- Moles of \(\text{Cl}_2\): \(0.287\) moles
- Volume of container: \(19.0\) L
- Temperature: \(832\) K
**Task:**
Calculate the equilibrium constant \(K_c\) for the reaction under the given conditions.
To do so, use the formula for the equilibrium constant:
\[
K_c = \frac{[\text{CO}][\text{Cl}_2]}{[\text{COCl}_2]}
\]
Where \([ \cdot ]\) represents the concentration in moles per liter. You will need to calculate the concentrations from the given moles and volume.
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