Consider the following reaction: CaCO3 (s) CaO (s) + CO2 (g) ΔΗ = + 177.8 kJ According to Le Chatelier's Principle, what affect does removing some carbon dioxide have on the reaction? Less products are formed Shifts the reaction to the right to form more calcium carbonate Shifts the reaction to the right to form more products Shifts the reaction to the left to form more calcium carbonate

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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
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### Chemical Equilibrium and Le Chatelier's Principle

**Consider the following reaction:**

\[ \text{CaCO}_3 \ (s) \ \rightleftharpoons \ \text{CaO} \ (s) \ + \ \text{CO}_2 \ (g) \qquad \Delta H \ = \ +177.8 \ kJ \]

**According to Le Chatelier's Principle, what effect does removing some carbon dioxide have on the reaction?**

**Options:**

1. Less products are formed.
2. Shifts the reaction to the right to form more calcium carbonate.
3. Shifts the reaction to the right to form more products.
4. Shifts the reaction to the left to form more calcium carbonate.

---

**Explanation:**

In the reaction given, calcium carbonate (CaCO\(_3\)) decomposes into calcium oxide (CaO) and carbon dioxide (CO\(_2\)). According to Le Chatelier's Principle, if a component of the reaction is removed, the system will adjust to counteract this change by shifting the equilibrium.

If carbon dioxide (CO\(_2\)) is removed from the system, the reaction will shift to the right to produce more carbon dioxide, thus forming more of the products (CaO and CO\(_2\)).

---

**Answer:** 

- Shifts the reaction to the right to form more products.
Transcribed Image Text:### Chemical Equilibrium and Le Chatelier's Principle **Consider the following reaction:** \[ \text{CaCO}_3 \ (s) \ \rightleftharpoons \ \text{CaO} \ (s) \ + \ \text{CO}_2 \ (g) \qquad \Delta H \ = \ +177.8 \ kJ \] **According to Le Chatelier's Principle, what effect does removing some carbon dioxide have on the reaction?** **Options:** 1. Less products are formed. 2. Shifts the reaction to the right to form more calcium carbonate. 3. Shifts the reaction to the right to form more products. 4. Shifts the reaction to the left to form more calcium carbonate. --- **Explanation:** In the reaction given, calcium carbonate (CaCO\(_3\)) decomposes into calcium oxide (CaO) and carbon dioxide (CO\(_2\)). According to Le Chatelier's Principle, if a component of the reaction is removed, the system will adjust to counteract this change by shifting the equilibrium. If carbon dioxide (CO\(_2\)) is removed from the system, the reaction will shift to the right to produce more carbon dioxide, thus forming more of the products (CaO and CO\(_2\)). --- **Answer:** - Shifts the reaction to the right to form more products.
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