Consider the following reaction at equilibrium. W(s) +6 HCI(g) WCI6(g) + 3 H2(g) with AHo= 60 kJ What will happen to the H2 concentration in the following scenarios? HCI(g) is added? a) H2 will increase b) H2 will decrease c) Nothing will happen 20)

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**Equilibrium Reaction and Effects on H₂ Concentration**

Consider the following reaction at equilibrium:
\[ \text{W(s)} + 6 \text{HCl(g)} \leftrightarrow \text{WCl}_6\text{(g)} + 3 \text{H}_2\text{(g)} \] with \( \Delta H^0 = 60 \text{ kJ} \)

### What will happen to the H₂ concentration in the following scenarios?

**20) HCl(g) is added:**
- **a)** H₂ will increase
- **b)** H₂ will decrease
- **c)** Nothing will happen

**21) W(s) is added:**
- **a)** H₂ will increase
- **b)** H₂ will decrease
- **c)** Nothing will happen

**Explanation:**
- **For Question 20:**
  - When HCl(g) is added, the system will aim to counteract this change by shifting the equilibrium to the right, producing more \( \text{WCl}_6\text{(g)} \) and \( \text{H}_2\text{(g)} \). Thus, the concentration of \( \text{H}_2\text{(g)} \) will increase. The correct answer is **a) H₂ will increase**.

- **For Question 21:**
  - Adding W(s), a solid, does not affect the equilibrium concentrations of gases or dissolved substances. Therefore, the concentration of \( \text{H}_2\text{(g)} \) will remain unchanged. The correct answer is **c) Nothing will happen**.
Transcribed Image Text:**Equilibrium Reaction and Effects on H₂ Concentration** Consider the following reaction at equilibrium: \[ \text{W(s)} + 6 \text{HCl(g)} \leftrightarrow \text{WCl}_6\text{(g)} + 3 \text{H}_2\text{(g)} \] with \( \Delta H^0 = 60 \text{ kJ} \) ### What will happen to the H₂ concentration in the following scenarios? **20) HCl(g) is added:** - **a)** H₂ will increase - **b)** H₂ will decrease - **c)** Nothing will happen **21) W(s) is added:** - **a)** H₂ will increase - **b)** H₂ will decrease - **c)** Nothing will happen **Explanation:** - **For Question 20:** - When HCl(g) is added, the system will aim to counteract this change by shifting the equilibrium to the right, producing more \( \text{WCl}_6\text{(g)} \) and \( \text{H}_2\text{(g)} \). Thus, the concentration of \( \text{H}_2\text{(g)} \) will increase. The correct answer is **a) H₂ will increase**. - **For Question 21:** - Adding W(s), a solid, does not affect the equilibrium concentrations of gases or dissolved substances. Therefore, the concentration of \( \text{H}_2\text{(g)} \) will remain unchanged. The correct answer is **c) Nothing will happen**.
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