### Consider the following method:```javastatic int stackStuff(int n) { Stack stack = new Stack<>(); for (int count = 0; count <= n; count++) { if (count % 2 == 0) { stack.push(count); } else { return stack.pop(); } } return 1;}```### Give the result of:`stackStuff(2) + stackStuff(0)`#### Explanation:The method `stackStuff` takes an integer `n` and performs the following operations:1. Initializes a new stack of integers.2. Iterates from `0` to `n` inclusive: - If the current counter `count` is even, it pushes `count` onto the stack. - If the current counter `count` is odd, it pops the top value from the stack and returns it.3. If none of the numbers are odd (or after processing all numbers), it returns `1`.#### Calculating `stackStuff(2)`:- `count = 0`: Pushes `0` onto the stack.- `count = 1`: Pops `0` from the stack and returns it.Result: `0`#### Calculating `stackStuff(0)`:- `count = 0`: Pushes `0` onto the stack.- Exits loop (since no odd numbers occur) and returns `1`.Result: `1`### Therefore, the answer to `stackStuff(2) + stackStuff(0)` is:`0 + 1 = 1`

Consider the following method: static int stackStuff (int n) { Stack stack = new Stack<>(); for (int count = 0; count <= n; count++) { if (count % 2 == 0) { stack.push(count); } } else { } return stack.pop(); } return 1; Give the result of: stackStuff (2) + stackStuff (0)

Consider the following method: static int stackStuff (int n) { Stack stack = new Stack<>(); for (int count = 0; count <= n; count++) { if (count % 2 == 0) { stack.push(count); } } else { } return stack.pop(); } return 1; Give the result of: stackStuff (2) + stackStuff (0)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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