Consider the following implementation of a queue using 2 stacks. Let S1 and S2 be the two stacks and initially are both empty. enqueue(x): Push x into S1. dequeue(x): If S2 is not empty, then pop an item from S2 and return it. If S2 is empty, pop all items from S1 and push them into S2, then pop an item S2 and return it. Show that the amortized cost for each queue operation is O(1).
Consider the following implementation of a queue using 2 stacks. Let S1 and S2 be the two stacks and initially are both empty. enqueue(x): Push x into S1. dequeue(x): If S2 is not empty, then pop an item from S2 and return it. If S2 is empty, pop all items from S1 and push them into S2, then pop an item S2 and return it. Show that the amortized cost for each queue operation is O(1).
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter18: Stacks And Queues
Section: Chapter Questions
Problem 16PE:
The implementation of a queue in an array, as given in this chapter, uses the variable count to...
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Consider the following implementation of a queue using 2 stacks. Let S1 and
S2 be the two stacks and initially are both empty.
enqueue(x): Push x into S1.
dequeue(x): If S2 is not empty, then pop an item from S2 and return it. If S2 is
empty, pop all items from S1 and push them into S2, then pop an item S2 and return
it.
Show that the amortized cost for each queue operation is O(1).
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