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Consider the following implementation of a bubble sort. Given an array a] containing n val- ues, the algorithm repeatedly scans the list from top to bottom. In each pass, adjacent entries are compared and swapped if they are in the wrong order. Assume that each instruction takes a constant amount of time. for (i=0; i

Consider the following implementation of a bubble sort. Given an array a] containing n val- ues, the algorithm repeatedly scans the list from top to bottom. In each pass, adjacent entries are compared and swapped if they are in the wrong order. Assume that each instruction takes a constant amount of time. for (i=0; i

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Consider the following implementation of a bubble sort. Given an array a] containing n val- ues, the algorithm repeatedly scans the list from top to bottom. In each pass, adjacent entries are compared and swapped if they are in the wrong order. Assume that each instruction takes a constant amount of time. for (i=0; i<n-1; i++) for (j=0; j<n-1-i; j++) if (a[j+1] < a[j]) { /* compare the two neighbors */ alj]; /* swap a[j] and a[j+1] */ tmp a[j] = a[j+1]; a[j+1] = tmp; (a) What is the best-case running time of this algorithm? Give the tightest asymptotic bound on the best-case running time using O notation. (b) What is the worst-base running time of this algorithm? Give the tightest asymptotic bound on the worst-case running time using O notation.
Transcribed Image Text:Consider the following implementation of a bubble sort. Given an array a] containing n val- ues, the algorithm repeatedly scans the list from top to bottom. In each pass, adjacent entries are compared and swapped if they are in the wrong order. Assume that each instruction takes a constant amount of time. for (i=0; i<n-1; i++) for (j=0; j<n-1-i; j++) if (a[j+1] < a[j]) { /* compare the two neighbors */ alj]; /* swap a[j] and a[j+1] */ tmp a[j] = a[j+1]; a[j+1] = tmp; (a) What is the best-case running time of this algorithm? Give the tightest asymptotic bound on the best-case running time using O notation. (b) What is the worst-base running time of this algorithm? Give the tightest asymptotic bound on the worst-case running time using O notation.
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