Consider the following hypothesis test.$ H_0: \sigma_1^2 = \sigma_2^2 $$ H_a: \sigma_1^2 \ne \sigma_2^2 $### (a) What is your conclusion if $ n_1 = 21, s_1^2 = 4.2, n_2 = 26, $ and $ s_2^2 = 2.0 $? Use $ \alpha = 0.05 $ and the p-value approach.#### Find the value of the test statistic.\[ \text{Test Statistic} = \]#### Find the p-value. (Round your answer to four decimal places.)\[ \text{p-value} = \]#### State your conclusion.- $\square$ Reject $ H_0 $. We cannot conclude that $ \sigma_1^2 = \sigma_2^2 $.- $\square$ Do not reject $ H_0 $. We cannot conclude that $ \sigma_1^2 \ne \sigma_2^2 $.- $\square$ Reject $ H_0 $. We can conclude that $ \sigma_1^2 \ne \sigma_2^2 $.- $\square$ Do not reject $ H_0 $. We can conclude that $ \sigma_1^2 = \sigma_2^2 $.### (b) Repeat the test using the critical value approach.#### Find the value of the test statistic.\[ \text{Test Statistic} = \]#### State the critical values for the rejection rule. (Round your answers to two decimal places. If you are only using one tail, enter NONE for the unused tail.)\[ \text{Test Statistic} \le \]\[ \text{Test Statistic} \ge \]#### State your conclusion.- $\square$ Reject $ H_0 $. We cannot conclude that $ \sigma_1^2 = \sigma_2^2 $.- $\square$ Do not reject $ H_0 $. We cannot conclude that $ \sigma_1^2 \ne \sigma_2^2 $.- $\square$ Reject $ H_0 $. We can conclude that \( \sigma_1^2 \ne \sigma_2

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Answered: Consider the following hypothesis test.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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