Consider the following hypothesis test.\( H_0: \sigma_1^2 = \sigma_2^2 \)\( H_a: \sigma_1^2 \ne \sigma_2^2 \)### (a) What is your conclusion if \( n_1 = 21, s_1^2 = 4.2, n_2 = 26, \) and \( s_2^2 = 2.0 \)? Use \( \alpha = 0.05 \) and the p-value approach.#### Find the value of the test statistic.\[ \text{Test Statistic} = \]#### Find the p-value. (Round your answer to four decimal places.)\[ \text{p-value} = \]#### State your conclusion.- \(\square\) Reject \( H_0 \). We cannot conclude that \( \sigma_1^2 = \sigma_2^2 \).- \(\square\) Do not reject \( H_0 \). We cannot conclude that \( \sigma_1^2 \ne \sigma_2^2 \).- \(\square\) Reject \( H_0 \). We can conclude that \( \sigma_1^2 \ne \sigma_2^2 \).- \(\square\) Do not reject \( H_0 \). We can conclude that \( \sigma_1^2 = \sigma_2^2 \).### (b) Repeat the test using the critical value approach.#### Find the value of the test statistic.\[ \text{Test Statistic} = \]#### State the critical values for the rejection rule. (Round your answers to two decimal places. If you are only using one tail, enter NONE for the unused tail.)\[ \text{Test Statistic} \le \]\[ \text{Test Statistic} \ge \]#### State your conclusion.- \(\square\) Reject \( H_0 \). We cannot conclude that \( \sigma_1^2 = \sigma_2^2 \).- \(\square\) Do not reject \( H_0 \). We cannot conclude that \( \sigma_1^2 \ne \sigma_2^2 \).- \(\square\) Reject \( H_0 \). We can conclude that \( \sigma_1^2 \ne \sigma_2

Answered: Image /qna-images/answer/e6e0999b-5972-4c4e-8fb0-f15577830c5c.jpg

Answered: Consider the following hypothesis test.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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