Consider the following hypothesis test:Ho: p 2 90Ha p< 90A sample of 150 is used and the population standard deviation is 12. Compute the p-value and state your conclusionfor each of the following sample results. Use a = 0.02, Round z value to two decimal places and p-value to fourdecimal places. If your answer is zero, enter "0". Enter negative value as negative number.a. = 89.5z valuep-valueconclusionSelect your answerHob. 7 = 86z valuep-valueconclusion -Select your answerv H,C. Z 852 valuep-value.conclusion l- Select your answer-v Hod. -91z-valueP-valueconclusion- Select your answer0Icon Key

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A variable has a mean of 100 and a standard deviation of 15. Nine observations of this variable have a mean of 109 and a sample standard deviation of 12. Determine the observed value of the a. standardized version of x. b. studentized version of x. a. z= (Round to three decimal places as needed.)
A particular fruit's weights are normally distributed, with a mean of 515 grams and a standard deviation of 36 grams. The heaviest 13% of fruits weigh more than how many grams? Give your answer to the nearest gram. Enter an integer or decimal number [more..] Submit Question 2 Type here to search hp esc 12 fs 2 3 4 LO 远 %24 %23
The shape of a given population distribution is normal with a mean of μ = 85 and a standard deviation of o= 6.5. For these parameters, transform a raw score of X = 100.5 into its corresponding z score. Round to the nearest tenths place if a fraction. The z score is: O 2.4 -3.7 -3.4 09.2 The correct z-score is not listed.
Scores for men on the verbal portion of the SAT-I test are normally distributed with a mean of 545 and a standard deviation of 112 . If 16 men are randomly selected, find the probability that their mean score is at least 590. a. Define the parameter A. x overbar equals The mean score of 16 randomly selected men B. x overbar equals The score of a randomly selected man b. State the mean of x overbar : nothing c. State the standard deviation of x overbar : nothing (use 2 decimal places) d. Find the z-score: nothing (use 2 decimal places) e. Find the probability: nothing (use 4 decimal places)
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). In this example, Hd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: Hd #0 H₁: Hd>0 O C. Ho: Hd #0 H₁: Hd=0 Identify the test statistic. t= (Round to two decimal places as needed.) B. Ho: Hd=0 H₁: Hd #0 O D. Ho: Hd = 0 H₁: Hd <0 More Info Household Paper 16.39 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 POTBRANN~~~~~~~ 7.57 11.42 6.44 20.12 2.41 6.05 2.80 13.61 13.05 17.65 8.72 6.16 7.72 7.98 6.38 6.67 6.98 29 11.08 5.86…
Use the sample data set to evaluate each of the steps in determining the sample standard deviation 23 20 14 35 28 Give an exact answer, not an approximation, for each step except the standard deviation. round the standard deviation to the nearest hundredth.. = = variance, s2 = standard deviation, s =
Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Refer to the accompanying data set. Use a 0.05 significance level to test the claim that women and men have the same mean diastolic blood pressure. a. The test statistic is (Round to two decimal places as needed.) b. The P-value is (Round to three decimal places as needed.)
A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.
The amount of coffee that people drink per day is normally distributed with a mean of 15 ounces and a standard deviation of 5.5 ounces. 16 randomly selected people are surveyed. Round all answers to 4 decimal places where possible. A.Find the IQR for the average of 16 coffee drinkers.Q1 = ounces Q3 = ounces IQR: ounces
Consider the following hypolhesis test: Ho : µ > 240 H. : µ < 240 A sample of 60 provided a sample mean of 234 and a sample standard deviation of 25. Find the value of the test statistic. Select one: O a. t = -1.86 Ob.t = -0.24 O c.t = -2.32 O d. t -0.30
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is…
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 161 adult males, the mean pulse rate is 69.2 bpm and the standard deviation is 11.3 bpm. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)

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