Consider the following galvanic cell and calculate the cell potential (Ecell). Co(s) | Co2"(aq, 0.15 M) || Fe*2(aq, 1.94 M) | Fe(s). = -0.28 V and E2+ Given: Eco2+/co = -0.447 V Fe2 0.0592 V Formulas: E°cell = E°cathode – E°anode and Nernst equation: Eell Ecell log Q %3D O -0.34 V O 0.34 V -0.24 V O - 0.13 V

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Consider the following galvanic cell and calculate the cell potential (Ecell).
Co(s) | Co2*(aq, 0.15 M) || Fe*2(aq, 1.94 M) | Fe(s).
= -0.28 V and Efe2+.
Given: Eco2+
= -0.447 V
Со
0.0592 V log Q
Formulas: E°cll
= E°cathode – E°anode and Nernst equation: E.ell =
Ecel
=
O -0.34 V
O 0.34 V
O-0.24 V
-0.13 V
Transcribed Image Text:Consider the following galvanic cell and calculate the cell potential (Ecell). Co(s) | Co2*(aq, 0.15 M) || Fe*2(aq, 1.94 M) | Fe(s). = -0.28 V and Efe2+. Given: Eco2+ = -0.447 V Со 0.0592 V log Q Formulas: E°cll = E°cathode – E°anode and Nernst equation: E.ell = Ecel = O -0.34 V O 0.34 V O-0.24 V -0.13 V
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