Consider the following family of series, one for each constant p > 0: 1 n(logn) S(p) = For each N > 2 we define the partial sum up to index N and the corresponding remainder as follows: SN (P) = N 1 n(logn)P (a) Express the following definite integral in terms of a, b, and p (assume a > 1): dx Sº x(log x) P RN(P) SSN(p). = a1 In(b)^(1-p)/(1-p)-In(a)^(1-p)/(1-P) Use p = 2.8 in all parts below. Please enter your answers in calculator ready form. (b) Express the following definite integral in terms of a (assume a > 1): Soz dx 1/(1.8ln^(1.8)(a)) x(log x) 2.8 (c) The integral test provides a two-sided inequality of the following form for RN (2.8) when N = 45: DO da < R4s (2.8) ≤2(log 2)2.8 用 Soz dx x(log x) 2.8 Find the integers a₁ and a₂ above. (Use the smallest compatible value of a₁ and the largest compatible value of a 2.) a2
Consider the following family of series, one for each constant p > 0: 1 n(logn) S(p) = For each N > 2 we define the partial sum up to index N and the corresponding remainder as follows: SN (P) = N 1 n(logn)P (a) Express the following definite integral in terms of a, b, and p (assume a > 1): dx Sº x(log x) P RN(P) SSN(p). = a1 In(b)^(1-p)/(1-p)-In(a)^(1-p)/(1-P) Use p = 2.8 in all parts below. Please enter your answers in calculator ready form. (b) Express the following definite integral in terms of a (assume a > 1): Soz dx 1/(1.8ln^(1.8)(a)) x(log x) 2.8 (c) The integral test provides a two-sided inequality of the following form for RN (2.8) when N = 45: DO da < R4s (2.8) ≤2(log 2)2.8 用 Soz dx x(log x) 2.8 Find the integers a₁ and a₂ above. (Use the smallest compatible value of a₁ and the largest compatible value of a 2.) a2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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