Consider the following equation. cos x = x3 (a) Prove that the equation has at least one real root. >v 0, and f(1) = cos 1 - 1z -0.46 v0 >v -0.46, there is a number c in (o, 1) such that f(x) = cos x - x is continuous on the interval [0, 1], f(0) = 1 f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x - x = 0 or cos x = x3, in the interval (0, 1). (b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Just part b

Consider the following equation.
cos x = x3
(a) Prove that the equation has at least one real root.
f(x) = cos x – x is continuous on the interval [0, 1], f(0) = 1
0, and f(1) = cos 1 – 1 x -0.46 < v 0. Since 1
v -0.46, there is a number c in (0, 1) such that
f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x – x
or cos x = x, in the interval (0, 1).
(b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)
Transcribed Image Text:Consider the following equation. cos x = x3 (a) Prove that the equation has at least one real root. f(x) = cos x – x is continuous on the interval [0, 1], f(0) = 1 0, and f(1) = cos 1 – 1 x -0.46 < v 0. Since 1 v -0.46, there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x – x or cos x = x, in the interval (0, 1). (b) Use your calculator to find an interval of length 0.01 that contains a root. (Enter your answer using interval notation.)
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