Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t) = Y(t)- Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20 2r(t) G = 50 E (t) = C(t)+1(t) + G AY(t+ 1) = 0.05 [E(t) - Y(t)] Ma(t) = 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1) = 0.8[Ma(t) - M₂(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t + 1) = 86a +(1− a)Y(t) + 0.6aY(t-1) - 2ar(t) r(t + 1) = -45ß +0.25BY(t) + (1 - 0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß= 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.] (iv) Use the spreadsheet this policy change? Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r are at their equilibrium values in periods 0 and 1. (iii) Use the model set up in the spreadsheet to calculate the new equilibrium output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the dynamic LM curve] to plot the trajectory of the economy resulting from
Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t) = Y(t)- Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20 2r(t) G = 50 E (t) = C(t)+1(t) + G AY(t+ 1) = 0.05 [E(t) - Y(t)] Ma(t) = 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1) = 0.8[Ma(t) - M₂(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t + 1) = 86a +(1− a)Y(t) + 0.6aY(t-1) - 2ar(t) r(t + 1) = -45ß +0.25BY(t) + (1 - 0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß= 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.] (iv) Use the spreadsheet this policy change? Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r are at their equilibrium values in periods 0 and 1. (iii) Use the model set up in the spreadsheet to calculate the new equilibrium output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the dynamic LM curve] to plot the trajectory of the economy resulting from
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Author:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Publisher:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Chapter5: Business And Economic Forecasting
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![Consider the following dynamic IS-LM model.
C(t) = 20+ 0.8Ya (t-1)
Ya(t) = Y(t) - Tx(t)
Tx(t) = 5 +0.25Y(t)
I(t) = 20 2r(t)
G = 50
E(t) = C(t) + 1(t) + G
AY(t + 1) = 0.05 [E(t) - Y(t)]
Ma(t) = 10+ 0.25Y(t) - 0.5r(t)
M, (t) = 55
Ar(t + 1) = 0.8[Ma(t)- M¸(t)]
(i) What is the equilibrium level of Y and r?
(ii) Show that dynamic IS and LM equations are the recursive equations for Y(+1) and
r(t+1). That is,
Y(t + 1) = 86a+ (1 -a)Y(t) + 0.6aY(t-1) - 2ar(t)
r(t + 1) = 45ß +0.25BY(t) + (1 - 0.5B)r(t)
where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of
money market adjustment. [Hint: Substitute all the relationships in each of the
adjustment equations in turn. The algebra can be somewhat tedious but not
intellectually difficult.]
(iv) Use the spreadsheet
this policy change?
Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r
are at their equilibrium values in periods 0 and 1.
(iii) Use the model set up in the spreadsheet
to calculate the new equilibrium
output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the
dynamic LM curve]
to plot the trajectory of the economy resulting from](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b2e65f2-c472-45bf-885c-00dffce84016%2F66d5f57d-fd20-439f-9318-e11029bf1d8c%2Fdjg2v_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following dynamic IS-LM model.
C(t) = 20+ 0.8Ya (t-1)
Ya(t) = Y(t) - Tx(t)
Tx(t) = 5 +0.25Y(t)
I(t) = 20 2r(t)
G = 50
E(t) = C(t) + 1(t) + G
AY(t + 1) = 0.05 [E(t) - Y(t)]
Ma(t) = 10+ 0.25Y(t) - 0.5r(t)
M, (t) = 55
Ar(t + 1) = 0.8[Ma(t)- M¸(t)]
(i) What is the equilibrium level of Y and r?
(ii) Show that dynamic IS and LM equations are the recursive equations for Y(+1) and
r(t+1). That is,
Y(t + 1) = 86a+ (1 -a)Y(t) + 0.6aY(t-1) - 2ar(t)
r(t + 1) = 45ß +0.25BY(t) + (1 - 0.5B)r(t)
where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of
money market adjustment. [Hint: Substitute all the relationships in each of the
adjustment equations in turn. The algebra can be somewhat tedious but not
intellectually difficult.]
(iv) Use the spreadsheet
this policy change?
Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r
are at their equilibrium values in periods 0 and 1.
(iii) Use the model set up in the spreadsheet
to calculate the new equilibrium
output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the
dynamic LM curve]
to plot the trajectory of the economy resulting from
![t
Y(t + 1) = 86a + (1 − a)Y(t) + 0.6aY(t− 1) −2ar(t)
r(t+1)= -xx.xß +0.25Y(t)+ (1 - 0.5p)r(t)
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Y(t)
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r(t)
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r3
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Monetary contraction
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alpha=
beta =
100
Y
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160
0.05
0.8
180
200](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b2e65f2-c472-45bf-885c-00dffce84016%2F66d5f57d-fd20-439f-9318-e11029bf1d8c%2Fbnyvx84_processed.png&w=3840&q=75)
Transcribed Image Text:t
Y(t + 1) = 86a + (1 − a)Y(t) + 0.6aY(t− 1) −2ar(t)
r(t+1)= -xx.xß +0.25Y(t)+ (1 - 0.5p)r(t)
0
1
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Y(t)
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r(t)
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r3
1
0
20
40
Monetary contraction
60
80
alpha=
beta =
100
Y
120
140
160
0.05
0.8
180
200
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