Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t)= Y(t) - Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20-2r(t) G = 50 E (t) = C(t) + 1(t) + G AY(t+1)= 0.05[E(t) - Y(t)] Ma(t)= 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1)=0.8 [Ma(t)-M,(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1) — 2ar(t) r(t + 1) = -45ß +0.25ẞY(t) + (1 -0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.]
Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t)= Y(t) - Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20-2r(t) G = 50 E (t) = C(t) + 1(t) + G AY(t+1)= 0.05[E(t) - Y(t)] Ma(t)= 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1)=0.8 [Ma(t)-M,(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1) — 2ar(t) r(t + 1) = -45ß +0.25ẞY(t) + (1 -0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.]
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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just ii please !!

Transcribed Image Text:t
Y(t + 1) = 86a + (1 − a)Y(t) + 0.6aY(t − 1) — 2ar(t)
r(t+1)= -xx.xß +0.25Y(t) + (1 - 0.5p)r(t)
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![Consider the following dynamic IS-LM model.
C(t) = 20 +0.8Y(t-1)
(iv)
Ya(t) = Y(t) - Tx(t)
Tx(t) = 5 +0.25Y(t)
I(t) = 20 2r(t)
G = 50
E (t) = C(t) + 1(t) + G
AY(t+1) = 0.05 [E(t) - Y(t)]
Ma(t) 10+ 0.25Y(t)
0.5r(t)
M,(t) = 55
Ar(t+1)=0.8 [Ma(t) - Ms(t)]
(i) What is the equilibrium level of Y and r?
(ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and
r(t+1). That is,
=
Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1)-2ar(t)
r(t + 1) = -45ß +0.25ßY(t) + (1 - 0.5B)r(t)
this policy change?
where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of
money market adjustment. [Hint: Substitute all the relationships in each of the
adjustment equations in turn. The algebra can be somewhat tedious but not
intellectually difficult.]
Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r
are at their equilibrium values in periods 0 and 1.
(iii)
calculate the new equilibrium
output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the
dynamic LM curve]
plot the trajectory of the economy resulting from](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b2e65f2-c472-45bf-885c-00dffce84016%2F0c623335-5e47-40fb-8a44-f27208759a78%2Frrdy5ik_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following dynamic IS-LM model.
C(t) = 20 +0.8Y(t-1)
(iv)
Ya(t) = Y(t) - Tx(t)
Tx(t) = 5 +0.25Y(t)
I(t) = 20 2r(t)
G = 50
E (t) = C(t) + 1(t) + G
AY(t+1) = 0.05 [E(t) - Y(t)]
Ma(t) 10+ 0.25Y(t)
0.5r(t)
M,(t) = 55
Ar(t+1)=0.8 [Ma(t) - Ms(t)]
(i) What is the equilibrium level of Y and r?
(ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and
r(t+1). That is,
=
Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1)-2ar(t)
r(t + 1) = -45ß +0.25ßY(t) + (1 - 0.5B)r(t)
this policy change?
where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of
money market adjustment. [Hint: Substitute all the relationships in each of the
adjustment equations in turn. The algebra can be somewhat tedious but not
intellectually difficult.]
Suppose the Reserve Bank reduces the money supply (Ms) to 53.6 in period 2, given Y and r
are at their equilibrium values in periods 0 and 1.
(iii)
calculate the new equilibrium
output and interest rate. [Hint: The LM curve shifts left so you need to re-calculate the
dynamic LM curve]
plot the trajectory of the economy resulting from
Expert Solution

Step 1: Define IS LM model
The IS-LM model is a macroeconomic framework used to analyze the relationship between real output (Y) and interest rates (r) in an economy. It was developed by John Hicks and Alvin Hansen in the 1930s and is an important part of Keynesian economics. The model consists of two main components: the IS curve and the LM curve.
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