Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t)= Y(t) - Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20-2r(t) G = 50 E (t) = C(t) + 1(t) + G AY(t+1)= 0.05[E(t) - Y(t)] Ma(t)= 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1)=0.8 [Ma(t)-M,(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1) — 2ar(t) r(t + 1) = -45ß +0.25ẞY(t) + (1 -0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.]
Consider the following dynamic IS-LM model. C(t) = 20+ 0.8Y(t-1) Ya(t)= Y(t) - Tx(t) Tx(t) = 5 +0.25Y(t) I(t) = 20-2r(t) G = 50 E (t) = C(t) + 1(t) + G AY(t+1)= 0.05[E(t) - Y(t)] Ma(t)= 10+ 0.25Y(t) - 0.5r(t) M₂(t) = 55 Ar(t+1)=0.8 [Ma(t)-M,(t)] (i) What is the equilibrium level of Y and r? (ii) Show that dynamic IS and LM equations are the recursive equations for Y(t+1) and r(t+1). That is, Y(t+1) = 86a + (1 − a)Y(t) + 0.6aY(t-1) — 2ar(t) r(t + 1) = -45ß +0.25ẞY(t) + (1 -0.5B)r(t) where a = 0.05 is the speed of good market adjustment and ß = 0.8 is the speed of money market adjustment. [Hint: Substitute all the relationships in each of the adjustment equations in turn. The algebra can be somewhat tedious but not intellectually difficult.]
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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just ii please !!
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Step 1: Define IS LM model
The IS-LM model is a macroeconomic framework used to analyze the relationship between real output (Y) and interest rates (r) in an economy. It was developed by John Hicks and Alvin Hansen in the 1930s and is an important part of Keynesian economics. The model consists of two main components: the IS curve and the LM curve.
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