Consider the following data regarding students' college GPAs and high school GPAs. The estimated regression equation is GPA). Estimated College GPA = 2.56 + 0.1582 High School GPA GPAs College GPA High School GPA 3.96 4.42 2.81 3.91 3.53 4.21 3.27 2.76 3.58 4.95 2.07 4.24 Copy Data Step 2 of 3: Compute the mean square error (s2) for the model. Round your answer to four decimal places.
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- Consider the following data regarding students' college GPAs and high school GPAs. The estimated regression equation is Estimated College GPA = 2.56 + 0.1582 (High School GPA). GPAs College GPA High School GPA 3.96 4.42 2.81 3.91 3.53 4.21 3.27 2.76 3.58 4.95 2.07 4.24 Copy Data Step 2 of 3: Compute the mean square error (s?) for the model. Round your answer to four decimal places.As an auto insurance risk analyst, it is your job to research risk profiles for various types of drivers. One common area of concern for auto insurance companies is the risk involved when offering policies to younger, less experienced drivers. The U.S. Department of Transportation recently conducted a study in which it analyzed the relationship between 1) the number of fatal accidents per 1000 licenses, and 2) the percentage of licensed drivers under the age of 21 in a sample of 42 cities. Your first step in the analysis is to construct a scatterplot of the data. FIGURE. SCATTERPLOT FOR U.S. DEPARTMENT OF TRANSPORATION PROBLEM U.S. Department of Transportation The Relationship Between Fatal Accident Frequency and Driver Age 4.5 3.5 3 2.5 1.5 1 0.5 6. 10 12 14 16 18 Percentage of drivers under age 21 Upon visual inspection, you determine that the variables do have a linear relationship. After a linear pattern has been established visually, you now proceed with performing linear…Consider the following data regarding students' college GPAs and high school GPAs. The estimated regression equation is Estimated College GPA = 0.84 + 0.531 (High School GPA). GPAs College GPA High School GPA 2.11 2.73 3.84 4.35 2.17 2.30 2.73 4.99 3.84 4.80 2.47 3.66 Copy Data Step 1 of 3: Compute the sum of squared errors (SSE) for the model. Round your answer to four decimal places.
- Find the regression equation, letting the first variable be the predictor (x) variable. Using the listed actress/actor ages in various years, find the best predicted age of the Best Actor winner given that the age of the Best Actress winner that year is 43 years. Is the result within 5 years of the actual Best Actor winner, whose age was 45 years? Best Actress 27 30 30 61 30 32 46 28 61 22 43 56 D Best Actor 42 39 38 45 51 49 59 51 38 57 45 34 Find the equation of the regression line. y = + (Round the constant to one decimal place as needed. Round the coefficient to three decimal places as needed.) The best predicted age of the Best Actor winner given that the age of the Best Actress winner that year is 43 years is years old. (Round to the nearest whole number as needed.) Is the result within 5 years of the actual Best Actor winner, whose age was 45 years? the predicted age is the actual winner's age.Consider the following data regarding students' college GPAs and high school GPAs. The estimated regression equation is Estimated College GPA = 4.59 + (-0.4391) (High School GPA PA). GPAs College GPA High School GPA 2.18 3.25 3.27 4.02 3.20 3.98 3.96 2.26 2.50 3.98 3.32 3.30 Copy Data Step 2 of 3: Compute the mean square error (s) for the model. Round your answer to four decimal places.Water is being poured into a large, cone-shaped cistern. The volume of water, measured in cm³, is reported at different time intervals, measured in seconds. A regression analysis was completed and is displayed in the computer output. Regression Analysis: cuberoot (Volume) versus Time Predictor Coef SE Coef Constant -0.006 0.00017 -35.294 0.000 Time 0.640 0.000018 35512.6 0.000 s=0.030 R-Sq=1.000 R-sq (adj)=1.000 What is the equation of the least-squares regression line? Volume = 0.640 - 0.006(Time) Volume = 0.640 - 0.006(Time) Volume = -0.006 + 0.640(Time) Volume = - 0.006 + 0.640(Time?)
- Expedia wants to use regression analysis to build a model for airfare tickets prices in the states: Ticket prices = 30 + B1*Miles + E where Miles is measured in hundreds Coefficients 169.50 5.90 Intercept Miles (in hundreds) Which of the following is true? Standard Error 1.34 0.09 4 t Stat 126.85 61.28 P-value 0.000 0.002 If Miles increases by 1, then we predict ticket price to go up by $5.9. O If ticket price goes up by $1, then we predict Miles to go up by 590 miles. O If ticket price goes up by $100, then we predict Miles to go up by 590 miles. If Miles increases by 100, then we predict ticket price to go up by $5.9.You are interested in the effect rainfall has on the number of traffic accidents in your city. You consider 4 possible specifications for a polynomial regression: (1) Accidents = 15.2 +0.23°Rain - 0.11*Rain2 + 0.08 Rain3 -0.0s Rain (7.1) (0.13) (0.05) (0.03) (0.02) (2) Accidents = 13.2 +0.14*Rain -0.09 Rain?+0.07 Rain3 (5.1) (0.05) (0.03) (0.04) (3) Accidents= 75+0.24*Rain - 0.13 Rain2 (3.6) (0.12) (0.07) (4) Accidents = 94 +0.18°Rain (2.3) (0.05) Based on a 5% significance level, which of the 4 specifications is the most appropriate model? O Specification1 O Specification 2 O Specification 3 O Specification 4 O None of them since Rain does not have a statistically significant effect on AccidentsTrue or False For a linear regression model including only an intercept, the OLS estimator of that intercept is equal to the sample mean of the independent variable.
- 1. Consider a linear regression model y = XB + € with E(e) = 0. The bias of the ridge estimator of 3 obtained by minimizing Q(B) = (y — Xß)¹ (y — Xß) + r(BTB), for some r > 0, is ——(X²X + r1)-¹8 1 (X¹X +rI)-¹3 r -r(XTX+rI) ¹8 r(X¹X+r1) ¹3How to run a linear regression analysis on excel based on the following data: Fatalities Ln Safety Belt Rate 1071 3.951243719 1138 4.058717385 996 4.257030144 991 4.374498368 1038 4.365643155 1004 4.348986781 1154 4.382026635 1148 4.404277244 1207 4.417635062 1110 4.410371108 969 4.455509411 848 4.49980967 862 4.515245478 895 4.477336814 865 4.494238625 853 4.577798989 820 4.561218298 850 4.535820108 1083 4.521788577 948 4.531523646 953 4.519612298 856 4.525044142Data is collected from a sample of 1,000 US households in an attempt to understand the relationship between income and money spent eating out at restaurants. A regression is estimated based on the data, and the equation is as follows: Spending; 10.12 + 0.25 * Income; + 756.48 * City: 122.96 * Children where restaurant spending and income are yearly values measure in $, city is a binary variable that takes on a 1 if the household lives in a city, and children is the number of children in the family. What is the predicted restaurant spending for a household with a yearly income of $50,000, not located in a city, and with 3 children? $12,387.16 $12,141.24 $12,131.12 $12,897.72