### Consider the following code:```pythons1 = 'astronomy's2 = 'astrology'k = 1i = 0while i < len(s1): if s1[0:k] == s2[0:k]: k += 1 i += 1```#### Question:What is the value of `s1[:k-1]` after executing the code above?#### Select one:- a. ast- b. astro- c. astrono- d. astronomy#### Explanation:The code snippet provided is a Python script with a `while` loop that compares substrings of `s1` and `s2` from the start up to `k` characters. The variable `k` starts at `1` and is incremented if the substrings `s1[0:k]` and `s2[0:k]` are equal.- Initially, `k = 1`, so it compares `s1[0:1]` with `s2[0:1]`. Since both are 'a', `k` is incremented to 2.- Next, `s1[0:2]` is compared with `s2[0:2]`. Both are 'as', so `k` is incremented to 3.- This continues with the comparisons resulting in 'ast', 'astr', and 'astro', until `s1[0:6]` ('astron') is compared with `s2[0:6]` ('astrol'). At this point, the substrings are no longer equal, so `k` is not incremented.Thus, the last increment occurs at 'astro'. Therefore, `k = 6` at the end. The calculated substring `s1[:k-1]` would be `s1[:5]`, which is 'astro'.#### Answer:- **b. astro**

Answer to the above question is in step2.

Consider the following code: sl='astronomy' s2='astrology' k = 1 i = 0 while i < len(s1): 6. 1 4 ...if sl[0:k] 7 s2 [0:k]: == ......k += 1 ...i += 1 8. What is the value of s1[:k-1] after executing the code above?

Consider the following code: sl='astronomy' s2='astrology' k = 1 i = 0 while i < len(s1): 6. 1 4 ...if sl[0:k] 7 s2 [0:k]: == ......k += 1 ...i += 1 8. What is the value of s1[:k-1] after executing the code above?

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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