Consider the following code segment. What is the value of i and sum2 after the for loop completes? int sum2 = 0, i = 0;for (int i = 0; i < 5; i++) sum2 = sum2 + i; cout << "Sum is: " << sum2 << " i is: " << i << endl;

Here, "for" loop executes 4 times because condition is less than 5. Initially, "sum2" is zero and "i" also zero. In first iteration, addition of (sum2 + i) is zero because both values are zero. Then in second iteration, i becomes 1 and addition (sum2 + i) becomes 1 i.e sum2 is 1. After that "i" becomes 2 and addition (sum2 + i) will become (1+2)=3 and value 3 is stored in "sum2". Then "i" becomes 3 and addition (sum2 + i) =(3 + 3)=6 and 6 will be stored in "sum2". After that "i" becomes 4 and addition (sum2 + i)=(6 + 4)=10 will be stored in "sum2" means sum2=10. At last, "i" becomes 5 and condition (i<5) will false and it comes outside the loop. Here, value of "sum2" is 10 after completion of "for" loop. But, value of "i" remains as it is i.e 0. Because in the iterations of "for" loop "i" becomes 5 but after successfully completion of "for" loop, value of "i" will not consider. The value of "i" will be that value which is initialized firstly i.e 0. The value of "i" in "for" loop will not consider outside "for" loop. The value of "i" will be considered 0 after completion of "for" loop. #include <iostream> using namespace std; int main(){ int sum2 = 0, i = 0; for (int i = 0; i < 5; i++) sum2 = sum2 + i; cout << "Sum is: " << sum2 << " i is: " << i << endl; return 0;}Output: