Consider the following beam section. It has a concrete compressive strength of 4,000 psi and Grade-60 bars. There are 4 #9 bars at the top and 9 #10 bars at the bottom. The area of a single #9 bar is 1.0 in.² and the area of a single #10 bar is 1.27 in.². The section is subjected to a positive moment with the top bars in compression.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Consider the following beam section. It has a concrete compressive strength of 4,000 psi and
Grade-60 bars. There are 4 #9 bars at the top and 9 #10 bars at the bottom. The area of a single
#9 bar is 1.0 in.² and the area of a single #10 bar is 1.27 in.². The section is subjected to a
positive moment with the top bars in compression.
5 in.
12 in.
10 in.
O
20 in.
оо
4 #9 bars
O
8 in.
9 #10 bars
10 in.
OF
2.75 in.
2.5 in.
2.5 in.
24 in.
Does the beam satisfy the tension-controlled condition of ACI 318
Transcribed Image Text:Consider the following beam section. It has a concrete compressive strength of 4,000 psi and Grade-60 bars. There are 4 #9 bars at the top and 9 #10 bars at the bottom. The area of a single #9 bar is 1.0 in.² and the area of a single #10 bar is 1.27 in.². The section is subjected to a positive moment with the top bars in compression. 5 in. 12 in. 10 in. O 20 in. оо 4 #9 bars O 8 in. 9 #10 bars 10 in. OF 2.75 in. 2.5 in. 2.5 in. 24 in. Does the beam satisfy the tension-controlled condition of ACI 318
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Answer 

ACI code 318 states that the member whose computed tensile strain 'εs' is equal to greater than the 0.005(εs 0.005)

at the same time the concrete strain is 0.003 are to be refered as tension controlled beam.

To calculate the tensile strain we have εs0.003(d-c)c

d = effective depth of beam

c = Neutral axis location from top

Calculation of 'd'

d = distance from extreme compression fibre to the centroid of steel bar 

d = h - centroid of steel bar from bottom

h = 10+12+5

h = 27 in 

To calculate centroid of steel bar from bottom we can use centroid formula

we have bottom 3-#10 bars centroid at 3 in from bottom, middle 3-#10 bars centroid at 5.5 in from bottom and top 3-#10  bars centroid at 8 in.

centroid of steel bar from bottom = 3*3+3*5.5+3*89   (since all 9- #10 bars have same area it will cancel out)

centroid of steel bar from bottom = 5.5 in

Now d = 27- 5.5

d = 21.5 mm

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