Consider the following balanced equation: 2 H2 + 02 -2 H20 What mass of water (H20) will be collected if 20.0 grams of oxygen gas (02) are consumed?

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Consider the following balanced equation: 2 H2 + O2 → 2 H2O
What mass of water (H2O) will be collected if 20.0 grams of oxygen gas (O2) are consumed?

(Mass of H2O = 18.02 g/mol and Mass of O2 = 32.00 g/mol)

Consider the following balanced equation: 2 H2 + 02 – 2 H20
What mass of water (H,0) will be collected if 20.0 grams of oxygen gas (0,) are consumed?
(Mass of H20 = 18.02 g/mol and Mass of O2 = 32.00 g/mol)
O a
11.31 grams of H,0
22.52 grams of H20
45.00 grams of H,0
90.10 grams of H,0
Transcribed Image Text:Consider the following balanced equation: 2 H2 + 02 – 2 H20 What mass of water (H,0) will be collected if 20.0 grams of oxygen gas (0,) are consumed? (Mass of H20 = 18.02 g/mol and Mass of O2 = 32.00 g/mol) O a 11.31 grams of H,0 22.52 grams of H20 45.00 grams of H,0 90.10 grams of H,0
Expert Solution
Step 1

From the given data,it is clear that

2 mol H2 +1 mol O2 2mol H2O

we know that ,1 mol of  a compound = molar mass of that compound

molar mass of O= 32 g/mol

Then, 1 mol of Ocontains 32 g of O2

Also,molar mass of H2O= 18.02 g/mol

Then, 1 mol of H2O contains 18.02 g of H2O

:. 2 mol of H2O contains  2 X 18.02 g of H2O

 

 

 

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