Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.

t = 1
t=2
t = 3
t = 4
t=5+
t = 15
t = 16
t = 17
t = 18
t = 19
QUESTION 2 OF 15
data segment
data segment
data segment
data segment
data segment →→→→
What is the sequence number of the segment sent at t=2?
←ACK segment
←ACK segment
ACK segment
ACK segment
t = 8
t = 9
t = 10
t = 11
t = 12
Transcribed Image Text:t = 1 t=2 t = 3 t = 4 t=5+ t = 15 t = 16 t = 17 t = 18 t = 19 QUESTION 2 OF 15 data segment data segment data segment data segment data segment →→→→ What is the sequence number of the segment sent at t=2? ←ACK segment ←ACK segment ACK segment ACK segment t = 8 t = 9 t = 10 t = 11 t = 12
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