Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest triangles can be written as a/c = e/a, and the ratios of the lengths of the corresponding sides of the largest and second largest triangles can be written as ______. Using the Cross Products Property, these can rewritten as a2= ce and _______. Then, by using substitution, a2 + b2=ce + cf. By factoring, a2 + b2= c (e+f). Next, by looking at the original triangle, (e+f) =c. Lastly, by using substitution, a2+b2=c (c)=c2. Consider the figure and the partially completed paragraph proof.baQeRCSince the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallestE, and the ratios of the lengths of the corresponding sides of the largest and secondUsing the Cross Products Property, these can be rewritten as a? = ce andce + cf. By factoring, a? + b² =c(e+f). Next, by looking at thetriangles can be written aslargest triangles can be written asThen, by.using substitution, a² + b2 :original triangle, (e+ f) = c. Lastly, by using substitution, a² + b? = c(c) = c².||

Answered: Image /qna-images/answer/49715d64-0e7a-49bf-a784-f0076e7a098b.jpg

Answered: Consider the figure and the partially…

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter4: Quadrilaterals

Section4.3: The Rectangle, Square, And Rhombus

Problem 42E: a Argue that the midpoint of the hypotenuse of a right triangle is equidistant from the three...

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Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest triangles can be written as a/c = e/a, and the ratios of the lengths of the corresponding sides of the largest and second largest triangles can be written as ______. Using the Cross Products Property, these can rewritten as a2= ce and _______. Then, by using substitution, a2 + b2=ce + cf. By factoring, a2 + b2= c (e+f). Next, by looking at the original triangle, (e+f) =c. Lastly, by using substitution, a2+b2=c (c)=c2.

Consider the figure and the partially completed paragraph proof.
b
a
Q
e
R
C
Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest
E, and the ratios of the lengths of the corresponding sides of the largest and second
Using the Cross Products Property, these can be rewritten as a? = ce and
ce + cf. By factoring, a? + b² =c(e+f). Next, by looking at the
triangles can be written as
largest triangles can be written as
Then, by.using substitution, a² + b2 :
original triangle, (e+ f) = c. Lastly, by using substitution, a² + b? = c(c) = c².
||

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

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