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Consider the falling object of mass m = assume that the drag force is proportional to the 12 kg, and square of velocity. Let the limiting velocity be vlim = 79 m/sec. If v(0) = 0, find the speed of the object at any time. 1 – e ²²v 0.02x9.8, 12 е v(t) = 12 x 1 + e^²√ 0.02×9.8 12 е -2. e v(t) = 79 x 1+e= ²√ 1 e-²v - v(t) = 79 x 1 + ²√ e v(t) = 12 x 1 + e 1+e v(t) = 79 x 1-e 0.02x9.8. 12 0.02x9.8. 12 0.02×9.8 12 0.02x9.8 12 0.02×9.8 12 0.02x9.8 12 0.02x9.8 12 0.02×9.8 12 -t -t

Consider the falling object of mass m = assume that the drag force is proportional to the 12 kg, and square of velocity. Let the limiting velocity be vlim = 79 m/sec. If v(0) = 0, find the speed of the object at any time. 1 – e ²²v 0.02x9.8, 12 е v(t) = 12 x 1 + e^²√ 0.02×9.8 12 е -2. e v(t) = 79 x 1+e= ²√ 1 e-²v - v(t) = 79 x 1 + ²√ e v(t) = 12 x 1 + e 1+e v(t) = 79 x 1-e 0.02x9.8. 12 0.02x9.8. 12 0.02×9.8 12 0.02x9.8 12 0.02×9.8 12 0.02x9.8 12 0.02x9.8 12 0.02×9.8 12 -t -t

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the falling object of mass m = 12 kg, and assume that the drag force is proportional to the square of velocity. Let the limiting velocity be vlim = 79 m/sec. If v(0) = 0, find the speed of the object at any time. 1 0.02x9.8. 12 e v(t) = 12 x 0.02x9.8 1+e 12 e v(t) = 79 x 1+e=²²√ е -2. 1- e v(t) = 79 x 1+e e v(t) = 12 x 1 + e 1 + e v(t) = 79 x 1 - e ² V 0.02×9.8 12 0.02x9.8 12 0.02x9.8 12 0.02x9.8. 12 0.02x9.8 12 0.02×9.8 12 0.02×9.8 12 0.02x9.8 12
Transcribed Image Text:Consider the falling object of mass m = 12 kg, and assume that the drag force is proportional to the square of velocity. Let the limiting velocity be vlim = 79 m/sec. If v(0) = 0, find the speed of the object at any time. 1 0.02x9.8. 12 e v(t) = 12 x 0.02x9.8 1+e 12 e v(t) = 79 x 1+e=²²√ е -2. 1- e v(t) = 79 x 1+e e v(t) = 12 x 1 + e 1 + e v(t) = 79 x 1 - e ² V 0.02×9.8 12 0.02x9.8 12 0.02x9.8 12 0.02x9.8. 12 0.02x9.8 12 0.02×9.8 12 0.02×9.8 12 0.02x9.8 12
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