Suppose we throw a stone up into the air. It's velocity in meters/sec after t seconds is given by v (t) = 30 – 10t (a) Find the displacement of the stone from t seconds. = 0 seconds to t 30 (b) Find the total distance the stone travels from t = 0 seconds to t = 30 seconds.

The braking distance d, in meters, of a vehicle traveling at a velocity v, in meters per second, is given by the formula d = 2ug* is the coefficient of friction and g is the acceleration due to gravity. On Earth, where gx9.8 m/s. Complete parts (a) and (b) below. (a) Determine the braking distance of a car traveling at 55 km/hr on dry pavement (u = 0.80). (Be sure to convert the speed to meters per second.) The braking distance is about meters. (Simplify your answer. Round to the nearest integer as needed.) (b) Determine the braking distance of a car traveling at 63 mi/hr on wet pavement (u = 0.45). Give the final answer in feet. The braking distance is about feet. (Round to the nearest ten as needed.)

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You are snowboarding and about to go over a jump. The total airtime you get is given as the function of your speed by:                                  t(s) = √s − 20 (airtime function) If you are currently traveling at 56m/s. a) Use the derivative of the airtime function to estimate how much extra airtime you will get for each added m/s of speed you have. b) Use the average rate of change equation to calculate the exact change in airtime for one added m/s of speed if you are traveling at 56m/s.