Consider the equilibrium system described by the chemical reaction below. For this reaction, Kp = 109 at 298 K. If the equilibrium partial pressures of Br. and NOBR at 0.0159 atm and 0.0768 atm, respectively, determine the partial pressure of NO at equilibrium.. 2 NO(g) + Br:(g) =2 NOBr(g) NEXT (x) represents the equilibrium partial pressure of NO, set up the equilibrium expression for Kp to plve for the partial pressure. Do not combine or simplify terms.. 109 %3D O RESET (109) (0.0159) (0.0768) 2(0.0159) 2(0.0768) (0.0159) (0.0768) (x) (2x) (x) (2x)

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