Consider the equilibrium between COBr2, CO and Br₂. COBr₂(g) CO(g) + Br₂(g) K 1.96 at 381 K The reaction is allowed to reach equilibrium in a 20.0-L flask. At equilibrium, [COBr₂] = 2.10×10-2 M, [CO] = 0.203 M and [Br₂] = 0.203 M. (a) The equilibrium mixture is transferred to a 10.0-L flask. In which direction will the reaction proceed to reach equilibrium? to the left (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 10.0-L flask. [COBr₂] = [Co] [Br₂] = ΣΣΣ
Consider the equilibrium between COBr2, CO and Br₂. COBr₂(g) CO(g) + Br₂(g) K 1.96 at 381 K The reaction is allowed to reach equilibrium in a 20.0-L flask. At equilibrium, [COBr₂] = 2.10×10-2 M, [CO] = 0.203 M and [Br₂] = 0.203 M. (a) The equilibrium mixture is transferred to a 10.0-L flask. In which direction will the reaction proceed to reach equilibrium? to the left (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 10.0-L flask. [COBr₂] = [Co] [Br₂] = ΣΣΣ
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Consider the equilibrium between COBr₂, CO and Br₂.
COBr₂(g) CO(g) + Br₂(g) K 1.96 at 381 K
The reaction is allowed to reach equilibrium in a 20.0-L flask. At equilibrium, [COBr₂] = 2.10×10-² M,
[CO] = 0.203 M and [Br₂] = 0.203 M.
(a) The equilibrium mixture is transferred to a 10.0-L flask. In which direction will the reaction proceed
to reach equilibrium?
to the left
(b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is
transferred to a 10.0-L flask.
[COBr₂] =
[CO]
[Br₂]
II
II
ΣΣΣ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1aba0b34-15dd-4381-a224-979828f87e27%2F4ddd6ec0-a98c-43cb-a1b2-e9b230f0e695%2F8dswxg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the equilibrium between COBr₂, CO and Br₂.
COBr₂(g) CO(g) + Br₂(g) K 1.96 at 381 K
The reaction is allowed to reach equilibrium in a 20.0-L flask. At equilibrium, [COBr₂] = 2.10×10-² M,
[CO] = 0.203 M and [Br₂] = 0.203 M.
(a) The equilibrium mixture is transferred to a 10.0-L flask. In which direction will the reaction proceed
to reach equilibrium?
to the left
(b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is
transferred to a 10.0-L flask.
[COBr₂] =
[CO]
[Br₂]
II
II
ΣΣΣ
![Some PCI, is allowed to dissociate into PCI3 and Cl₂ at 523 K. At equilibrium, [PCI5] = 0.216 M, and
[PCI3] = [Cl₂] = 0.104 M. Additional PCI, is added so that [PCI5]new = 0.354 M and the system is allowed
to once again reach equilibrium.
PCI5(g) PCI3(g) + Cl₂(g)
(a) In which direction will the reaction proceed to reach equilibrium? [
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?
[PCI5] =
[PCI3] =
[Cl₂]
=
K= 5.01x10-2 at 523 K
ΣΣΣ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1aba0b34-15dd-4381-a224-979828f87e27%2F4ddd6ec0-a98c-43cb-a1b2-e9b230f0e695%2F6ja3ra8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Some PCI, is allowed to dissociate into PCI3 and Cl₂ at 523 K. At equilibrium, [PCI5] = 0.216 M, and
[PCI3] = [Cl₂] = 0.104 M. Additional PCI, is added so that [PCI5]new = 0.354 M and the system is allowed
to once again reach equilibrium.
PCI5(g) PCI3(g) + Cl₂(g)
(a) In which direction will the reaction proceed to reach equilibrium? [
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?
[PCI5] =
[PCI3] =
[Cl₂]
=
K= 5.01x10-2 at 523 K
ΣΣΣ
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