Consider the equation. g(x) h(y) dA = g(x) h(y) dy ) dx = dy dx Use the above equation to evaluate the given integral. dA, R = [0, 3] × [0, 2] IR × + 1
Consider the equation. g(x) h(y) dA = g(x) h(y) dy ) dx = dy dx Use the above equation to evaluate the given integral. dA, R = [0, 3] × [0, 2] IR × + 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Consider the equation.**
\[
\int_{R} g(x) \, h(y) \, dA = \int_{a}^{b} \left( \int_{c}^{d} g(x) \, h(y) \, dy \right) dx = \int_{a}^{b} g(x) \left( \int_{c}^{d} h(y) \, dy \right) dx
\]
\[
= \left( \int_{a}^{b} g(x) \, dx \right) \left( \int_{c}^{d} h(y) \, dy \right)
\]
**Use the above equation to evaluate the given integral.**
\[
\int_{R} \int \frac{y}{x+1} \, dA, \quad R = [0, 3] \times [0, 2]
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e824278-0cf8-4697-a6ac-3768c642cb77%2F9a06fa8a-6058-4cee-8d34-83c6377732df%2F5dmkvqj_processed.png&w=3840&q=75)
Transcribed Image Text:**Consider the equation.**
\[
\int_{R} g(x) \, h(y) \, dA = \int_{a}^{b} \left( \int_{c}^{d} g(x) \, h(y) \, dy \right) dx = \int_{a}^{b} g(x) \left( \int_{c}^{d} h(y) \, dy \right) dx
\]
\[
= \left( \int_{a}^{b} g(x) \, dx \right) \left( \int_{c}^{d} h(y) \, dy \right)
\]
**Use the above equation to evaluate the given integral.**
\[
\int_{R} \int \frac{y}{x+1} \, dA, \quad R = [0, 3] \times [0, 2]
\]
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