Consider the differential equation Y+ 2y = 4x - 3e*, given that y(0) = 1 and y (0) = 2. What would be the yp? Yp = x2 - x- e* B Yp = - x² +4 – ex ©Yp = x²+4- 2e-2x D Yp = - x² +4-2e-2x

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 7RE: Does the equation y=2.294e0.654t representcontinuous growth, continuous decay, or neither?Explain.
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Consider the differential equation Y+2y - 4x-3e*, given that y(0)-1 and y (0)- 2, what would be the yp?
%3D
A
A Yp x2 -x- ex
B
Yp=-x²+4- e
CY,= x2 +4-2e 2x
D Yp=-x²+4-2e-2x
Ур
D
E Yp=x2 + 4 – e*
Transcribed Image Text:Consider the differential equation Y+2y - 4x-3e*, given that y(0)-1 and y (0)- 2, what would be the yp? %3D A A Yp x2 -x- ex B Yp=-x²+4- e CY,= x2 +4-2e 2x D Yp=-x²+4-2e-2x Ур D E Yp=x2 + 4 – e*
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