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demand function: 3000 f(n) = 4 + (100 ≤ n ≤1500) n + 100 where n is the number of tee shirts that can be sold per month at a price of f(n) dollars per shirt. 41. At a price level of $19 per shirt, compare the predictions for monthly sales obtained using each model. Hint: You need to solve each of the equations p(n) = 19 and f(n) = 19 and interpret the results. 42. Show that at a price level of $10 per shirt, the model p predicts more than twice as many sales per month as does the model t Hint: Solve each of the equations n(n) = 10 1 2 $ @ 4 3 % olo5 66 & 7 8 9 0 O P { delete

demand function: 3000 f(n) = 4 + (100 ≤ n ≤1500) n + 100 where n is the number of tee shirts that can be sold per month at a price of f(n) dollars per shirt. 41. At a price level of $19 per shirt, compare the predictions for monthly sales obtained using each model. Hint: You need to solve each of the equations p(n) = 19 and f(n) = 19 and interpret the results. 42. Show that at a price level of $10 per shirt, the model p predicts more than twice as many sales per month as does the model t Hint: Solve each of the equations n(n) = 10 1 2 $ @ 4 3 % olo5 66 & 7 8 9 0 O P { delete

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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demand function: 3000 f(n) = 4 + (100 ≤ n ≤1500) n + 100 where n is the number of tee shirts that can be sold per month at a price of f(n) dollars per shirt. 41. At a price level of $19 per shirt, compare the predictions for monthly sales obtained using each model. Hint: You need to solve each of the equations p(n) = 19 and f(n) = 19 and interpret the results. 42. Show that at a price level of $10 per shirt, the model p predicts more than twice as many sales per month as does the model t Hint: Solve each of the equations n(n) = 10 1 2 $ @ 4 3 % olo5 66 & 7 8 9 0 O P { delete
Transcribed Image Text:demand function: 3000 f(n) = 4 + (100 ≤ n ≤1500) n + 100 where n is the number of tee shirts that can be sold per month at a price of f(n) dollars per shirt. 41. At a price level of $19 per shirt, compare the predictions for monthly sales obtained using each model. Hint: You need to solve each of the equations p(n) = 19 and f(n) = 19 and interpret the results. 42. Show that at a price level of $10 per shirt, the model p predicts more than twice as many sales per month as does the model t Hint: Solve each of the equations n(n) = 10 1 2 $ @ 4 3 % olo5 66 & 7 8 9 0 O P { delete
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