Consider the differential equation dy/dt = 2√|y|. (a) Show that the function y(t) = 0 for all t is an equilibrium solution. (b) Find all solutions. [Hint: Consider the cases y > 0 and y < 0 separately. Then you need to define the solutions using language like “y(t) = . . . when t ≤ 0 and y(t) = . . . when t > 0.”] (c) Why doesn’t this differential equation contradict the Uniqueness Theorem?
Consider the differential equation dy/dt = 2√|y|. (a) Show that the function y(t) = 0 for all t is an equilibrium solution. (b) Find all solutions. [Hint: Consider the cases y > 0 and y < 0 separately. Then you need to define the solutions using language like “y(t) = . . . when t ≤ 0 and y(t) = . . . when t > 0.”] (c) Why doesn’t this differential equation contradict the Uniqueness Theorem?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the
(a) Show that the function y(t) = 0 for all t is an equilibrium solution.
(b) Find all solutions. [Hint: Consider the cases y > 0 and y < 0 separately. Then
you need to define the solutions using language like “y(t) = . . . when t ≤ 0
and y(t) = . . . when t > 0.”]
(c) Why doesn’t this differential equation contradict the Uniqueness Theorem?
(d) What does HPGSolver do with this equation?
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