Consider the diagram below for free energy (G) versus fraction of A reacted in terms of moles for the reaction Alg) - B(g). Before any A has reacted. PA- 3.0 atm and Pg - 0. What is the value of Kp and the sign of AG° for this reaction? 0.33 0.67 1.00 Fraction of A reacted OA Ko-0.5 and AG<0 OB. Kp- 1/9 and AG<0 OC Kp-1 and AG <0 OD. Kp- 1/9 and AG>o E. Kp-05 and AG0
Consider the diagram below for free energy (G) versus fraction of A reacted in terms of moles for the reaction Alg) - B(g). Before any A has reacted. PA- 3.0 atm and Pg - 0. What is the value of Kp and the sign of AG° for this reaction? 0.33 0.67 1.00 Fraction of A reacted OA Ko-0.5 and AG<0 OB. Kp- 1/9 and AG<0 OC Kp-1 and AG <0 OD. Kp- 1/9 and AG>o E. Kp-05 and AG0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Understanding Free Energy Changes in Chemical Reactions**
**Description:**
Consider the diagram below for free energy (G) versus the fraction of A reacted in terms of moles for the reaction \( A(g) \rightarrow B(g) \). Before any A has reacted, \( P_A = 3.0 \) atm and \( P_B = 0 \). What is the value of \( K_p \) and the sign of \( \Delta G^\circ \) for this reaction?
**Graph Explanation:**
- **Y-Axis (Vertical):** Represents the free energy (G).
- **X-Axis (Horizontal):** Represents the fraction of substance A that has reacted.
- **Curve Shape:** The curve initially decreases, reaching a minimum around a fraction of 0.33 reacted, and then rises steadily beyond this point up to a fraction of 1.00 reacted.
**Options:**
- A. \( K_p = 0.5 \) and \( \Delta G^\circ < 0 \)
- B. \( K_p = 1/9 \) and \( \Delta G^\circ < 0 \)
- C. \( K_p = 1 \) and \( \Delta G^\circ < 0 \)
- D. \( K_p = 1/9 \) and \( \Delta G^\circ > 0 \)
- E. \( K_p = 0.5 \) and \( \Delta G^\circ > 0 \)
**Instruction:**
Analyze the given information and the behavior of the free energy curve to determine the correct option regarding the equilibrium constant \( K_p \) and the standard change in free energy \( \Delta G^\circ \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff364b906-934b-4f43-b7b4-bcc25ebe3486%2F00d12cf1-f131-40e9-aee6-78c79ba52b08%2Foepr28m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Understanding Free Energy Changes in Chemical Reactions**
**Description:**
Consider the diagram below for free energy (G) versus the fraction of A reacted in terms of moles for the reaction \( A(g) \rightarrow B(g) \). Before any A has reacted, \( P_A = 3.0 \) atm and \( P_B = 0 \). What is the value of \( K_p \) and the sign of \( \Delta G^\circ \) for this reaction?
**Graph Explanation:**
- **Y-Axis (Vertical):** Represents the free energy (G).
- **X-Axis (Horizontal):** Represents the fraction of substance A that has reacted.
- **Curve Shape:** The curve initially decreases, reaching a minimum around a fraction of 0.33 reacted, and then rises steadily beyond this point up to a fraction of 1.00 reacted.
**Options:**
- A. \( K_p = 0.5 \) and \( \Delta G^\circ < 0 \)
- B. \( K_p = 1/9 \) and \( \Delta G^\circ < 0 \)
- C. \( K_p = 1 \) and \( \Delta G^\circ < 0 \)
- D. \( K_p = 1/9 \) and \( \Delta G^\circ > 0 \)
- E. \( K_p = 0.5 \) and \( \Delta G^\circ > 0 \)
**Instruction:**
Analyze the given information and the behavior of the free energy curve to determine the correct option regarding the equilibrium constant \( K_p \) and the standard change in free energy \( \Delta G^\circ \).
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