Consider the database schema below. Fruit (ID: integer, Name: String ) Vitamin (FruitID: Integer. VitaminName: String, VitaminPercentage) A Fruit name can have null value? O No, violates domain constraints. O No, violates entity Integrity constraint O Yes. O No, violates key constraint. O No, violates referential integrity constraint.

Consider the database schema below. Fruit (ID: integer, Name: String ) Vitamin (FruitID: Integer. VitaminName: String, VitaminPercentage) A Fruit name can have null value? O No, violates domain constraints. O No, violates entity Integrity constraint O Yes. O No, violates key constraint. O No, violates referential integrity constraint.

A Guide to SQL

9th Edition

ISBN:9781111527273

Author:Philip J. Pratt

Publisher:Philip J. Pratt

Chapter2: Database Design Fundamentals

Section: Chapter Questions

Problem 11RQ

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Database course: Convert the following ER diagram into a relational database schema, be certain to indicate primary keys and referential integrity constraints. (The photos complete each other) (I need the answer to copy it please)
FileStructure and Database CourseConsider the LIBRARY relational database schema shown in Figure 8.14, which is used to keep track of books, borrowers, and book loans. Referential integrity constraints are shown as directed arcs in Figure 8.14, as in the notation of Figure 5.7. Write down relational expressions also write the queries in SQL statements. for the following queriesFigure 8.18 will be attached a. How many copies of the book titled The Lost Tribe are owned by the library branch whose name is ‘Sharpstown’?c. Retrieve the names of all borrowers who do not have any books checked out.e. For each library branch, retrieve the branch name and the total number of books loaned out from that branch.g. For each book authored (or coauthored) by Stephen King, retrieve the title and the number of copies owned by the library branch whose name is Central.
QUESTION 3 Consider the database schema below. Fruit (ID: integer, Name: String ) Vitamin (FruitID: Integer, VitaminName: String, VitaminPercentage) Two Fruit records with different FruitID can have the same Name? O Yes. No, violates key constraint. O No, violates referential integrity constraint. No, violates domain constraints. O No, violates entity Integrity constraint
true /false The system-defined database used as a template for all “to be created” databases is the tempdb database. The entire contents of this database, including database options, are copied to the new database. Thus, if you modify this database, all databases created afterward will inherit those changes. OUTER JOIN types return only non-matching tuples. When we create a primary key (PK) some Database Management Systems (DBMS) automaticallly create a Foreign Key constraint on the attributes of the PK. SQL Server DBMS is one of these DBMSs. If a relation has more than one candidate key, we can implement this by creating a Primary Key constraint for one of the candidate keys, and a UNIQUE constraint for each and every one of the alternate keys. Using the Query Editor Window, “select TOP 1000 Rows” retrieves the first 1000 tuples of a relation (assuming that the relation has 1000 or more tuples). If there is…
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Consider the following relations: Employee(E_id: integer, E_name: string, Age: integer, Salary: real) Works(E_id: integer, Dep_id: integer, Start_date: date) Department(Dep_id: integer, Dep_name: string, Budget: real, Manager_E_id: integer) What referential integrity constraints exist between these relations? What are the options for enforcing these constraints when a user attempts to delete a Dept tuple?
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TASK 1 1. The InstantRide Management team founded a new team for car maintenance. The new team is responsible for the small maintenance operations for the cars in the InstantRide system. The main idea is to take actions faster and minimize the time spent for the maintenance. Therefore, the Car Maintenance team wants to store MAINTENANCE_TYPE_ID (char(5)) and a MAINTENANCE_TYPE_DESCRIPTION (varchar(30)) in the database. Using MAINTENANCE_TYPE_ID as the PRIMARY KEY, cook up a new table, MAINTENANCE_TYPES, and send the table description with the column names and types to the Car Maintenance team. Task: Make a new table to store car maintenance types. Task 2: The Car Maintenance team also wants to store the actual maintenance operations in the database. The team wants to start with a table to store CAR_ID (CHAR(5)), MAINTENANCE_TYPE_ID (CHAR(5)) and MAINTENANCE_DUE (DATE) date for the operation. Make a new table named MAINTENANCES. The PRIMARY_KEY should be the combination of the…
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