Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction SLL S10, $3,4 What is the value of the element pointed by arrow number 1 by in hexadecimal or binary? Note that the PC and the content of registers are found in bottom left of the figure below Address Select one Oa. Ox00000000 Ob. Ob 10011' Oc 0x0000AF00 ® d. 06/01000 Oe. None of the options Of Ox000000BA LEY Content 0x000016EC Dx0000ABOD Data Memory 0x000016F0 0x00A01245 0x000016F4 0x00001A42 Ox000171C 0x0008124 0x0001720 0x00021345 0x0001724 0x000067AB 0x0001734 0x0001738 0x0000A835 0x0000FA72 0x000174C 0x0000AC $63 0x000000BA PC = 0x000FAC04 Register File and PC (Before executing SLL)

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