Consider the crank assembly of the figure. The bearings at points A and B are in good alignment, and thus generate only force reactions (no moment reactions). Bearing B in NOT a thrust bearing and thus can exert reaction force in an x-z plane only (not in the “y" direction). Bearing A is a thrust bearing, and can thus exert rcaction forcc in any dircction. The force at point C is given: Fc = 10 î – 5 j– 80 k lbs.The force applied at point D is horizontal; i.e., P=- Pî. The Cartesian coordinates of key points are given below (in inches) for your convenience: Point A: [ 0,0, 0 ]; Point B: [ 0, 28, 0 ]; Point C: [ –10, 14, 0 ]; Point D [ 0, –10, –8 ] Determine (express all vectors in Cartesian-vector form): 1. The position vector: ľB/A = AB 2. The position vector: ľca = AC 3. The position vector: TDA = AD %3D Fe 4. The moment vector: °MA (the moment about point A due to the force vector Fc). 5. The moment vector: 'MA (the moment about point A due to the force vector P). The result here will be expressed in term of the unknown magnitude P. 6. The moment vector: "MA (the moment about point A due to the reaction-force vector B). The result here will be expressed in terms of the unknown Cartesian components Bx and Bz; recall By=0. 7. Using the given figure (included on the next page), complete the free-body diagram (FBD) of the crank bar DACB. If applicable, distinguish moment vectors from force vectors using double arrowheads for moment vectors. 8. Write the equations of equilibrium and solve to determine the unknown force magnitude P and the reaction force vectors A and B.