Consider the compound aluminum chloride. What is the wavelength and frequency capable of accomplishing the third ionization energy of aluminum? If an ionized electron was moving at an identical frequency and wavelength, what would be the speed of the electron?

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A: A→=5.3 mcos12°i^+5.3 msin12°j^=5.184 m  i^+1.102 m j^B→=-2 mcos45°i^+2 msin45°j^=-1.414 m  i^+1.414…

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A: Given,  M = 3 î + 4 ĵ – 4 k^ N = î − 4 ĵ −  k^

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