Consider the Common Emitter (CE) amplifier below. The capacitor Cn = 1 µF, Vcc = 12 V, ßr = 150, and the low cut-off frequency is 100 Hz. Assume Vaɛ = 0.7 V. Væsat for this BJT transistor is 0.2 V. Rc = 8002, and Re=120 2. The quiescent collector current is 5 mA Vcc Re2 Rc Vour Cin RE (1) Draw the small signal model for the CE amplifier (11) What is the transconductance gain of the amplifier? (111) What is the voltage gain of the amplifier – with and without a bypass capacitor (C:)? (IV) Determine a suitable value for the bypass capacitor CE.
Consider the Common Emitter (CE) amplifier below. The capacitor Cn = 1 µF, Vcc = 12 V, ßr = 150, and the low cut-off frequency is 100 Hz. Assume Vaɛ = 0.7 V. Væsat for this BJT transistor is 0.2 V. Rc = 8002, and Re=120 2. The quiescent collector current is 5 mA Vcc Re2 Rc Vour Cin RE (1) Draw the small signal model for the CE amplifier (11) What is the transconductance gain of the amplifier? (111) What is the voltage gain of the amplifier – with and without a bypass capacitor (C:)? (IV) Determine a suitable value for the bypass capacitor CE.
Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:Consider the Common Emitter (CE) amplifier below. The capacitor Cn = 1 µF, Vcc
= 12 V, Br = 150, and the low cut-off frequency is 100 Hz. Assume VBE = 0.7 V.
VCE SAT for this BJT transistor is 0.2 V. Rc = 8002, and Re=120 2. The quiescent
collector current is 5 mA
Rg2
Rc
VIN H
Cin
R81
RE
CE
(1) Draw the small signal model for the CE amplifier
(11) What is the transconductance gain of the amplifier?
(II) What is the voltage gain of the amplifier – with and without a bypass
capacitor (Ce)?
(IV) Determine a suitable value for the bypass capacitor CE.
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