Answered: Consider the combustion of 2.89 mol of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the combustion of 2.89 mol of liquid ethanol (C2H5OH) to gaseous water and car-bon dioxide. Calculate the enthalpy change for this reaction. The pertinent enthalpies of formation (in kJ/mol) are∆Hf H2O=−241.8∆Hf CO2=−393.5∆Hf C2H5OH=−277.7Answer in units of kJ

Expert Solution

Step 1

Step 1) The combustion of ethanol will leads to give water and carbon dioxide.

Reaction is as followed:

$C_{2} H_{5} OH + 3 O_{2} \to 2 {CO}_{2} + 3 H_{2} O$

Firstly, finding the moles of each using stoichiometry.

$moles of C_{2} H_{5} OH = 2.89 mole moles of {CO}_{2} = 2.89 moles of C_{2} H_{5} OH \times \frac{2 mol of {CO}_{2}}{1 mole of C_{2} H_{5} OH} 5.78 moles of {CO}_{2} moles of H_{2} O = 2.89 moles of C_{2} H_{5} OH \times \frac{3 mole of H_{2} O}{1 mole of C_{2} H_{5} OH} 8.67 mole of H_{2} O moles of O_{2} = 2.89 moles of C_{2} H_{5} OH \times \frac{3 mole of O_{2}}{1 mole of C_{2} H_{5} OH} 8.67 mole of O_{2}$

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