Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 70.0% of its initial charge. Assume the circuit has a time constant of 18.7 s. (a) Calculate the time interval required (in s) for the capacitor to reach this charge. 6.668 (b) If R = 300 kn, what is the value of C (in µF)?
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- In the circuit below the value of the resistance 14 Ω and the value of the capacitance is 2.0 µF. The voltage of the battery is 50 V. The capacitor is initially uncharged. Sometime after the switch is closed, the current in the circuit is measured to be 1.1 A. At this time, what is the charge on the capacitor, in µC? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.The circuit in the figure below contains a 90.0 V battery and four capacitors. In the top parallel branch, there are two capacitors, one with a capacitance of C, = 6.00 uf and another with a capacitance of 6.00 uF. In the bottom parallel branch, there are two more capacitors, one with a capacitance of 2.00 uF and another with a capacitance of C, = 8.00 pF. 6.00 uF 2.00 uF 90.0 V (a) What is the equivalent capacitance (in uF) of the entire circuit? (b) What is the charge (in uC) on each capacitor? on C, on C2 on the 6.00 uF capacitor pc on the 2.00 uF capacitor (c) What is the potential difference (in V) across each capacitor? across C, across C, V across the 6.00 µF capacitor across the 2.00 pF capacitorTwo capacitors are connected in series between the terminals of a 20.0-V battery. If their capacitances are 35.0 µF and 46.0 µF, determine the following. (a) the equivalent capacitance of the system (b) the magnitude of charge stored on each plate of either capacitor (c) the voltage across the 35.0 µF capacitor (Give your answer to at least one decimal place.) (d) the voltage across the 46.0 µF capacitor