***Consider the circuit shown in figure 3, assume that Vin =21 sin (wt) (in V), to answer Q6 and Q7. Q6) The DC output voltage Vode (in V) is: A) 8.91 B) 13.38 C) 6.68 Q7) The peak inverse voltage of D1 (PIV) (in V) is at least: A) 14 B) 12 e) 15 D) 21 Vin D1 2k PIV VO + 4k Figure 3 1k +Ve D) 11.14 E) 12.89 E) 9 F20.50 BV1 -21+1/2+41+21=0 I = 21 713 Vo=12 -Ve-21+4B1=0 I= 5:25 Vo=zi BVI 115 (3m) +12-PIV=0 F) 18 = 3m
***Consider the circuit shown in figure 3, assume that Vin =21 sin (wt) (in V), to answer Q6 and Q7. Q6) The DC output voltage Vode (in V) is: A) 8.91 B) 13.38 C) 6.68 Q7) The peak inverse voltage of D1 (PIV) (in V) is at least: A) 14 B) 12 e) 15 D) 21 Vin D1 2k PIV VO + 4k Figure 3 1k +Ve D) 11.14 E) 12.89 E) 9 F20.50 BV1 -21+1/2+41+21=0 I = 21 713 Vo=12 -Ve-21+4B1=0 I= 5:25 Vo=zi BVI 115 (3m) +12-PIV=0 F) 18 = 3m
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![***Consider the circuit shown in figure 3, assume that Vin =21 sin (wt) (in V), to answer Q6 and Q7.
Q6) The DC output voltage Vode (in V) is:
A) 8.91
B) 13.38
C) 6.68
Q7) The peak inverse voltage of D1 (PIV) (in V) is at least:
A) 14
B) 12
C) 15
D) 21
Vin
D1
2k
PIV
VO +
4k
Figure 3
1k
+ Ve
D) 11.14
E) 12.89
E) 9
F) 20.50
BV1 - 21+1/2+41+21=0
I = 21
7/13
Vo=12
-Ve-21+4BI=0
1=525
Vo=21
BVI 11(3m/+12 -P7V = 0
F) 18
- 3m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F925c5b43-0ff5-423d-b41d-47f31ad381c6%2F1dc1fe01-6389-486d-99d1-5b18d11699d1%2F2lb4p9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:***Consider the circuit shown in figure 3, assume that Vin =21 sin (wt) (in V), to answer Q6 and Q7.
Q6) The DC output voltage Vode (in V) is:
A) 8.91
B) 13.38
C) 6.68
Q7) The peak inverse voltage of D1 (PIV) (in V) is at least:
A) 14
B) 12
C) 15
D) 21
Vin
D1
2k
PIV
VO +
4k
Figure 3
1k
+ Ve
D) 11.14
E) 12.89
E) 9
F) 20.50
BV1 - 21+1/2+41+21=0
I = 21
7/13
Vo=12
-Ve-21+4BI=0
1=525
Vo=21
BVI 11(3m/+12 -P7V = 0
F) 18
- 3m
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