Consider the circuit shown below. (The capacitors are initially uncharged.) R C1 R C2 S lust after the sw chỉ closed, current supplied by the battery is zero R 28 R 28 2R 2R J impossible to determine.

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### Electrical Circuit Analysis

Consider the circuit shown below. (The capacitors are initially uncharged.)

**Diagram Explanation:**
- A circuit is drawn with a battery of electromotive force \(\mathcal{E}\).
- There are two resistors, each with resistance \(R\), and two capacitors, \(C_1\) and \(C_2\).
- The resistors and capacitors are arranged as follows:
  - The circuit branches into two parallel paths after the switch \(S\).
  - Each path contains one resistor and one capacitor.
  - Both branches reconvene before reconnecting with the negative terminal of the battery.

**Question:**
Just after the switch is closed, the current supplied by the battery is:

- ○ zero
- ○ \(\frac{\mathcal{E}}{R}\)
- ○ \(\frac{2\mathcal{E}}{R}\)
- ○ \(\frac{2\mathcal{E}}{2R}\)
- ○ \(\frac{\mathcal{E}}{2R}\)
- ○ impossible to determine.

### Analysis:
At the moment the switch is closed, the capacitors behave like short circuits since they are initially uncharged. Therefore, the current can be calculated as if the capacitors were not present. The solution requires understanding the initial condition of the circuit at the moment the switch is closed. Select the correct current expression from the given options.
Transcribed Image Text:### Electrical Circuit Analysis Consider the circuit shown below. (The capacitors are initially uncharged.) **Diagram Explanation:** - A circuit is drawn with a battery of electromotive force \(\mathcal{E}\). - There are two resistors, each with resistance \(R\), and two capacitors, \(C_1\) and \(C_2\). - The resistors and capacitors are arranged as follows: - The circuit branches into two parallel paths after the switch \(S\). - Each path contains one resistor and one capacitor. - Both branches reconvene before reconnecting with the negative terminal of the battery. **Question:** Just after the switch is closed, the current supplied by the battery is: - ○ zero - ○ \(\frac{\mathcal{E}}{R}\) - ○ \(\frac{2\mathcal{E}}{R}\) - ○ \(\frac{2\mathcal{E}}{2R}\) - ○ \(\frac{\mathcal{E}}{2R}\) - ○ impossible to determine. ### Analysis: At the moment the switch is closed, the capacitors behave like short circuits since they are initially uncharged. Therefore, the current can be calculated as if the capacitors were not present. The solution requires understanding the initial condition of the circuit at the moment the switch is closed. Select the correct current expression from the given options.
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