Consider the circuit diagram in the figure. Ɛ1 = 18 V 0.5 Q R 2.5 0 R a 6.0 2 R 1.5 2 12 0.50 E2 = 45 V a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? b) If the current through the middle part of the loop is 4 = 4.75 amps, what is the current through the top loop, /2, in amps?

Consider the circuit diagram in the figure. Ɛ1 = 18 V 0.5 Q R 2.5 0 R a 6.0 2 R 1.5 2 12 0.50 E2 = 45 V a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? b) If the current through the middle part of the loop is 4 = 4.75 amps, what is the current through the top loop, /2, in amps?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Consider the circuit diagram in the figure.
E1= 18 V
0.5 Q
R
2.5 0
12
R,
a
6.0 2
R
1.5 2
0.5 0
E2 = 45 V
a) What is the equation which results when
applying the loop rule to loop aedcba, in
terms of the variables given in the figure?
b) If the current through the middle part of
the loop is 4 = 4.75 amps, what is the
current through the top loop, 2, in amps?

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