Consider the balanced chemical reaction below. If 24.3 g of iron is produced when 50.0 g of iron(III) oxide and 50.0 g of carbon monoxide react, what is the percentage yield of the reaction? Fe203(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) 1 3 NEXT Based on your knowledge of stoichiometry, set up the table below to determine the amounts of each reactant and product after the reaction goes to completion (assume 100% yield). Fe,03(s) 3 CO(g) 2 Fe(s) 3 CO2(g) + Before (mol) Change (mol) After (mol)
Consider the balanced chemical reaction below. If 24.3 g of iron is produced when 50.0 g of iron(III) oxide and 50.0 g of carbon monoxide react, what is the percentage yield of the reaction? Fe203(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) 1 3 NEXT Based on your knowledge of stoichiometry, set up the table below to determine the amounts of each reactant and product after the reaction goes to completion (assume 100% yield). Fe,03(s) 3 CO(g) 2 Fe(s) 3 CO2(g) + Before (mol) Change (mol) After (mol)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![On this educational page, we explore a stoichiometry problem based on a balanced chemical reaction.
**Scenario:**
Consider the reaction of iron(III) oxide with carbon monoxide:
\[ \text{Fe}_2\text{O}_3(\text{s}) + 3 \text{CO}(\text{g}) \rightarrow 2 \text{Fe}(\text{s}) + 3 \text{CO}_2(\text{g}) \]
When 50.0 g of iron(III) oxide and 50.0 g of carbon monoxide react, the reaction produces 24.3 g of iron. The task is to calculate the percentage yield of the reaction.
**Instructions:**
Using stoichiometry, determine the moles of each reactant and product when the reaction proceeds to completion, assuming a 100% yield. Follow the reaction table for calculations.
**Reaction Table:**
| Component | Fe₂O₃(s) | 3 CO(g) | → | 2 Fe(s) | + | 3 CO₂(g) |
|---------------|----------|---------|---|---------|---|----------|
| **Before (mol)** | | | | | | |
| **Change (mol)** | | | | | | |
| **After (mol)** | | | | | | |
Below the table, buttons display various values, likely useful for calculating moles or finding the limiting reactant.
**Detailed Explanation:**
- **Before (mol):** Initial moles of reactants.
- **Change (mol):** Moles consumed/produced during the reaction.
- **After (mol):** Remaining moles of reactants/products formed after the reaction.
Use the given masses and molar masses to perform stoichiometric conversions and fill in the table. After solving, compare actual to theoretical yield to find percentage yield.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F998b6cca-58bb-4391-bb13-94678d180001%2F9cc3b768-f261-430e-8222-4b3331a940a9%2Fvcnlj9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:On this educational page, we explore a stoichiometry problem based on a balanced chemical reaction.
**Scenario:**
Consider the reaction of iron(III) oxide with carbon monoxide:
\[ \text{Fe}_2\text{O}_3(\text{s}) + 3 \text{CO}(\text{g}) \rightarrow 2 \text{Fe}(\text{s}) + 3 \text{CO}_2(\text{g}) \]
When 50.0 g of iron(III) oxide and 50.0 g of carbon monoxide react, the reaction produces 24.3 g of iron. The task is to calculate the percentage yield of the reaction.
**Instructions:**
Using stoichiometry, determine the moles of each reactant and product when the reaction proceeds to completion, assuming a 100% yield. Follow the reaction table for calculations.
**Reaction Table:**
| Component | Fe₂O₃(s) | 3 CO(g) | → | 2 Fe(s) | + | 3 CO₂(g) |
|---------------|----------|---------|---|---------|---|----------|
| **Before (mol)** | | | | | | |
| **Change (mol)** | | | | | | |
| **After (mol)** | | | | | | |
Below the table, buttons display various values, likely useful for calculating moles or finding the limiting reactant.
**Detailed Explanation:**
- **Before (mol):** Initial moles of reactants.
- **Change (mol):** Moles consumed/produced during the reaction.
- **After (mol):** Remaining moles of reactants/products formed after the reaction.
Use the given masses and molar masses to perform stoichiometric conversions and fill in the table. After solving, compare actual to theoretical yield to find percentage yield.
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