Consider the balanced chemical reaction below. How many grams of CgH;Brare produced if 30.0 g of C6H6 and 66.0 g of Br, react and the percentageyield of the reaction is 73%?C6H6(g) + Br2(g)→C6H;Br(g) + HBr(g)AREV1NEXT>Based on the set up your table from the previous step, determine the maximum number ofgrams of C6H5BR that can be produced.XXXX河河河 xㄨX我** xXXKKXXmassc.H;Br =gRESET30.065.060.031.81.803.6163.960.3 Consider the balanced chemical reaction below. How many grams of C6H;B.are produced if 30.0 g of C6Hs and 66.0 g of Brz react and the percentageyield of the reaction is 73%?C6H6(g) + Br2(g)C6HsBr(g) + HBr(g)PREV1Based on your answer from the previous step and the given percent yield, determine theactual yield of C,H;Br.massc.H;Br1RESET21.947.543.823.31.312.6446.644.0

Given : Balanced chemical equation, First calculate the limiting reactant to get theoretical yield of C6H5Br.Convert the given grams of C6H6 in moles as shown below, 30.0 gC6H6×1 mol C6H678.1134g C6H6=0.384 molC6H6 Using mole ratio between C6H6 and C6H5Br, calculate number of moles of C6H5Br that can be produced from moles of C6H6 , 0.384 mol C6H6×1 mol C6H5Br1 mol C6H6=0.384 molC6H5Br Convert the given grams of Br2 in moles as shown below, 66.0 g Br2×1 mol Br2159.81 g Br2=0.413 mol Br2 Using mole ratio between Br2 and C6H5Br, calculate number of moles of C6H5Br that can be produced from moles of Br2 , 0.413 mol Br2×1 mol C6H5Br1 mol Br2=0.413 mol C6H5Br As per above calculated data, C6H6 produces less number of C6H5Br. Thus, C6H6 is a limiting reactant. The moles of C6H5Br can be produced = 0.384 mol Convert the above moles into grams as, 0.384 mol C6H5Br×157.01 gC6H5Br1 molC6H5Br =60.3 g C6H5Br Thus, theoretical yield of C6H5Br is 60.3 g. The formula for percent yield is, Percent yield =actual yieldtheoretical yield ×100 Rearranging the formula for actual yield, Actual yield =percent yield×theoretical yield100=73×60.3g100=44.0 g Therefore, the actual yield of C6H5Br is 44.0 g.

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Consider the balanced chemical reaction below. How many grams of C6H5BR are produced if 30.0 g of C6H6 and 66.0 g of Br2 react and the percentage yield of the reaction is 73%? C6H6(g) + Br2(g) → C6H;Br(g) + HBr(g) 昭EV 2. 1 3 NEXT Based on the set up your table from the previous step, determine the maximum number of grams of C6H5Br that can be produced. masscH;Br

Consider the balanced chemical reaction below. How many grams of C6H5BR are produced if 30.0 g of C6H6 and 66.0 g of Br2 react and the percentage yield of the reaction is 73%? C6H6(g) + Br2(g) → C6H;Br(g) + HBr(g) 昭EV 2. 1 3 NEXT Based on the set up your table from the previous step, determine the maximum number of grams of C6H5Br that can be produced. masscH;Br

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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