Consider the area A of the surface of revolution made by rotating the curvey=cot (x) from z=0 to z=7. Which of the following will give us this area? O 2= J0.75 25 cot(x)√1+ cac(x) dz 7 csc(x) √/1 + cot(x)4 dz - cot(z) 4 √/1 + cac(x)ª dz 75 2= √ √/cot (x) + cac(x)4 dz 0.75 24 / 7 cot(x) (1 + cac(x)2) dz 0.75 Note: Trigonometric squares are shown as f(x)², not f(x). For example sin(x) instead of sin(x).

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A: The area enclosed by a polar curve is given by the formula:

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